Evaluate the limit...
1 answer:
Answer:
Answer is c
Step-by-step explanation:
Given an expression in n as
We are asked to find out the limit as n tends to infinity
The given term has degree 1 for n in the numerator and degree 2 for n in the denominator
When n tends to infinity, since n is very large, we can say n^2>n
IN other words denominator having square of n approaches infinity faster than the numerator
This gives the limit as a finite value/infinite =0
HEnce limit =0
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Given:
The coordinates of point K' are (6,5).
K' is the image of K after a reflection in the line y=2.
To find:
The coordinates of point K.
Solution:
Let the coordinates of point K are (a,b).
If a figure is reflected over the line y=2, then
Using this formula, the coordinates of image of K are
The coordinates of point K' are (6,5).
On comparing both sides, we get
Therefore, the coordinates of point K are (6,-1).