Stand form of a circle is (x-h)²+(y-k)²=r², (h,k) being the coordinates for the center of the circle, r is the radius.
use the given three points to find the three unknown constants h, k, and r
(3-h)²+(1-k)²=r²
(-2-h)²+(6-k)²=r²
(-5-h)²+(-3-k)²=r²
expand these three equations:
9-6h+h²+1-2k+k²=r²
4+4h+h²+36-12k+k²=r²
25+10h+h²+9+6k+k²=r²
subtract equation 1 from equation 2, you get: 10h-10k=-30, h-k=-3
subtract equation 2 from equation 3, you get: 6h+18k=6, h+3k=1
subtract one form the other: 4k=4, k=1
h=1-3k=-2
find r²: (3+2)²+(1-1)²=r², (r=5)
so the equation is (x+2)²+(y-1)²=5²
Answer:
All are rational.
Step-by-step explanation:
1)
=1/3/3/5
=1/3×5/3
=5/9
5/9 is non-terminating and recurring number so it is rational.
2)
4/3√9/5
=4/3*3/5
=4/5
4/5 is a terminating number it is rational.
3)
2*√16/√4
=2*4/2
=4
4 is a natural/whole number it is also rational.
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Answer:
idk becaysurv5ktnf sksv2c1osbe
Answer:
x=1+√5 or x=1−√5
Step-by-step explanation:
x² - x - 12 ≠ 0
x² - 4x + 3x - 12 ≠ 0
x (x - 4) + 3 (x - 4) ≠ 0
(x + 3)(x - 4) ≠ 0
x ≠ -3 or x ≠ 4
(B)
