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Airida [17]
3 years ago
7

Plz i need help and plz explain

Mathematics
1 answer:
Montano1993 [528]3 years ago
3 0

\frac{ {x}^{2}  - 7x + 12}{ {x}^{2} - x - 12 }  \\  =  \frac{ {x}^{2} - 4x - 3x + 12 }{ {x}^{2} - 4x + 3x - 12 }  \\  =  \frac{x(x - 4) - 3(x - 4)}{x(x - 4) + 3(x - 4)}  \\  =  \frac{(x - 3)(x - 4)}{(x + 3)(x - 4)}  \\  =  \frac{x - 3}{x + 3}

x² - x - 12 ≠ 0

x² - 4x + 3x - 12 ≠ 0

x (x - 4) + 3 (x - 4) ≠ 0

(x + 3)(x - 4) ≠ 0

x ≠ -3 or x ≠ 4

(B)

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A ship at position (1, 0) on a nautical chart (with north in the positive y direction) sights a rock at position (7, 5). What an
Romashka-Z-Leto [24]

Answer:

0.69473828 radians east of north.

Step-by-step explanation:

Interpreting the information given on a Cartesian plane, the position of the ship will be (1,0) and that of the rock will be (7,5). Connecting the point (1,0) and (7,5) with a line and dropping a perpendicular line from point (7,5) to the x-axis to intersect the x-axis at (7,0), will form a right-triangle with base length 6 units and a height of 5 units.

<u>Finding the base length from points (1,0) and (7,0)</u>

d=√(x₂-x₁)²+(y₂-y₁)²

d=√(7-1)²

d= √6²

d=6 units

<u>Finding the height from points (7,5) and (7,0)</u>

d=√(x₂-x₁)²+(y₂-y₁)²

d=√(7-7)² + (0-5)²

d=√-5²

d=√25

d=5 units

So you now have a right triangle with base length 6 units and height 5 units.

To get the bearing of rock from ship position you apply the formula for tangent of an angle

Tan Ф = length of opposite side/length of adjustment side

TanФ=5/6

Tan Ф =0.83333333333

Tan⁻¹ (0.83333333333) =0.69473828 radians east of north.

3 0
3 years ago
Plz help me im stuck
Alexus [3.1K]
The answer is mostly likely B
7 0
3 years ago
Which of the following sets of number does square of 121 NOT belong
madreJ [45]

Answer:

D

Step-by-step explanation:

Squaring 121 will still be a real number, a rational number, and an integer. Therefore, it is not an irrational number.

8 0
3 years ago
how do you solve 2e - 12 = 7e + 8? i got 4 but the answer key says it's -4. what do you subtract from both sides?
ella [17]
First you subtract -2e from both side
7 0
3 years ago
Read 2 more answers
Simplity (4^-2)^5<br> A.1/4^10<br> B. 4^3<br> C.1/4^3<br> D. 4^10
Goshia [24]

Answer:

(4^{-2})^5=\dfrac{1}{4^{10}}

Step-by-step explanation:

The given expression is : (4^{-2})^5

We need to simplify the above expression.

We know that, x^{-a}=\dfrac{1}{x^a}

or

(4^{-2})^5=(\dfrac{1}{4^2})^5\\\\=\dfrac{1^5}{(4^2)^5}\\\\\because (x^b)^c=x^{b\times c}\\\\=\dfrac{1}{4^{10}}

So, the simplified form of the given expression is \dfrac{1}{4^{10}}. Hence, the correct option is (A).

5 0
3 years ago
Read 2 more answers
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