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3 years ago

More 5th grade work c’mon

Mathematics

1 answer:

fgiga [73]3 years ago

6 0

Answer: honestly for the first one, i think the answer would be 2.

they both have 5 at the end so you know its divisible :)

Step-by-step explanation:

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11/(x+9)=5<br> I am struggling with this question. Is there a solution?

maks197457 [2]

Answer:

x=-6.8

$\\ step \: by \: step \: explanation \\ \frac{11}{(x + 9)} = 5 \\ 11 = 5(x + 9) \\ 11 = 5x + 45 \\ 5x = 11 - 45 \\ 5x = - 34 \\ x = \frac{ - 34}{5} = - 6.8$

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3 years ago

What is the value of x in the equation −x = 4 − 3x + 6? (5 points)

san4es73 [151]

I think the answer is x=5

7 0

3 years ago

Read 2 more answers

The hypotenuse of a right

Lina20 [59]

None I would think because none of them are them because if you it is not the

8 0

3 years ago

Find the mean of the data in the dot plot below. Make sure to show your work and explain the steps you took in solving the probl

zaharov [31]

Answer: 6.

Step-by-step explanation: To find the mean, the first step is to add all the data together. Here's how it should look:

2 + 3 + 6 + 6 + 7 + 8 + 8 + 8 = 48.

Next, you need to divide whatever you get after adding the data by how many numbers there are for your data. In this case, 48 was the answer when we added all the data. In total, you have 8 numbers in your data, so you need to divide 8 from 48. It should look like this:

48 / 8 = 6.

Therefore, the mean for this data set is 6.

Have a great day! :)

5 0

2 years ago

Identify the radius and center.<br><br> x^2 + y^2 - 2x + 4y - 11 = 0

miss Akunina [59]

<h2>Hello!</h2>

The answer is:

Center: (1,-2)

Radius: 4 units.

To solve the problem, using the given formula of a circle, we need to find its standard equation form which is equal to:

$(x-h)^{2}+(y-k)^{2}=r^{2}$

Where,

"h" and "k"are the coordinates of the center of the circle and "r" is its radius.

So, we need to complete the square for both variable "x" and "y".

The given equation is:

$x^2+y^2-2x+4y-11=0$

So, solving we have:

$x^2+y^2-2x+4y=11$

$(x^2-2x+(\frac{2}{2})^{2} )+(y^2+4y+(\frac{4}{2})^{2})=11+(\frac{2}{2})^{2} +(\frac{4}{2})^{2}\\\\(x^2-2x+1)+(y^2+4y+4)=11+1+4\\\\(x^2-1)+(y^2+2)=16$

$(x^2-1)+(y^2-(-2))=16$

Now, we have that:

$h=1\\k=-2\\r=\sqrt{16}=4$

So,

Center: (1,-2)

Radius: 4 units.

Have a nice day!

Note: I have attached a picture for better understanding.

5 0

3 years ago