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FinnZ [79.3K]
3 years ago
12

Solve the exponential question . Leave your answer as a fraction

Mathematics
1 answer:
Doss [256]3 years ago
7 0

Step-by-step explanation:

problem → 2^x = 4, solve for x

⇒2^x=4

⇒2^x=2^2

⇒x=2

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What is LCM of two numbers if one number is a multiple of the other?Give on Example.
miv72 [106K]

Answer:

the greater number will be the lcm if the other number is a multiple

Step-by-step explanation:

for example: the lcm of 2 and 4

the lcm is 4 as 2 and 4 are both multiples of 4

4 0
3 years ago
Read 2 more answers
Please help me please.
shtirl [24]

Answer:

The first one is 79

The second one is 26

I hope this helped! :D

Step-by-step explanation:

For the first one you just plug in 23 into x so it would be 3(23) + 10 = x

For the second one you just plug in 88 into g so it would be 88 = 3x + 10

6 0
3 years ago
1 Without graphing, determine the characteristics of the graph.
olga nikolaevna [1]

Answer: (3, -1)

Step-by-step explanation:

y = |x-3|-1

When y=|x|, vertex is (0, 0).

Now, let's translate the graph so it becomes y = |x-3|-1.

|x| ==> |x-3|         Translate the graph 3 units to the right

Vertex: (0+3, 0) ==> (3, 0)

|x-3| ==> |x-3|-1     Translate the graph 1 unit down

Vertex: (3, 0-1) ==> (3, -1)

Vertex: (3, -1)

7 0
2 years ago
THIS IS TIMES I ONLY HAVE 5 MINUTES LEFT PLEASE SOMEONE HELP!!
Delvig [45]

Answer:

A. 10+10+5x=80 or 20+5x=80

B. Disagree, After the pay for each person to get in the have 60 dollars left. Each ride costs 5 dollars. 60 divided by 5=12 and each of them would need a ticket, so they could only ride 6 rides/

C. 20/5=4=they could by an additional 4 tickets, each would need a ticket so they could ride 2 more rides each

Step-by-step explanation:

80-20=60

60/5=12

3 0
3 years ago
Read 2 more answers
What is the value of -3|15 - s| + 2s3 when's = -3
slamgirl [31]
<span>-3|15 - s| + 2s^3 when s = -3 is
</span>-3|15 - (-3)| + 2(-3)^3 = <span>-3|15 + 3| + 2(-27) = </span><span>-3|18| + (-54) = -3(18) - 54 = -54 - 54 = -108</span>
6 0
3 years ago
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