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Arada [10]
2 years ago
8

In the drawing below, what choice shows the corresponding sides as equal ratios?

Mathematics
1 answer:
Leya [2.2K]2 years ago
6 0

Considering the similarity of triangles, the corresponding sides are:

\frac{DE}{AB} = \frac{EF}{BC} = \frac{DF}{AC}.

<h3>What are similar triangles?</h3>

If two triangles have the exact same angles, they are called similar, and the corresponding sides, that is, the sides adjacent to the same angles, have proportional lengths.

In this problem, the corresponding sides have equal ratios given as follows:

\frac{DE}{AB} = \frac{EF}{BC} = \frac{DF}{AC}.

More can be learned about similarity of triangles at brainly.com/question/11920446

#SPJ1

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Answer:

C. Point A is the center of the circle that passes that passes through the points E, F and G and is the center of the circle that passes through the points X, Y and Z.

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The center of insribed circle into the triangle is the point where the angle bisectors of the triangle meet.

The center of circumsribed circle over the triangle is the point where the perpendicular bisectors of the sides meet.

Line segments ZE, FY and GX are both angle bisectors and perpendicular bisectors of the sides, so the point of intersection of line segments ZE, FY and GX is the center of inscribed circle into the triangle and the center of the circumscribed circle over the triangle. Inscribed circle passes through the points X, Y and Z. Circumscribed circle passes through the points E, F and G. So, point A is the center of the circle that passes that passes through the points E, F and G and is the center of the circle that passes through the points X, Y and Z.

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1/7 times x = 1<br> 5/4 times x=1<br> 3 1/2 times x=1<br> 5/7 times x=1
antiseptic1488 [7]
( i )

=  > \frac{1}{7}  \times x = 1 \\  \\  \\  \\  =  >  \frac{1}{7}  \times 7  \times x = 1 \times 7 \\  \\  \\  \\  =  > x = 7



( ii ) :


=  >  \frac{5}{4}  \times x = 1 \\  \\  \\  \\  =  >  \frac{5}{4}  \times  \frac{4}{5}   \times  x = 1 \times  \frac{4}{5}  \\  \\  \\  \\  = > x =  \frac{4}{5}



( iii ) :


=  >  3\frac{1}{2}    \times x = 1 \\  \\  \\  \\   =  >  \frac{7}{2}  \times x = 1 \\  \\  \\  \\  =  >  \frac{7}{2}  \times  \frac{2}{7}  \times x = 1 \times  \frac{2}{7}  \\  \\  \\  \\  =  > x =  \frac{2}{7}



( iv ) :


\frac{5}{7}  \times x = 1 \\  \\  \\  \\  =  >  \frac{5}{7}  \times  \frac{7}{5}  \times x = 1 \times  \frac{7}{5}  \\  \\  \\  \\  =  > x =  \frac{7}{5}
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The gymnastics center where Shannon works has a rectangular pit filled with foam. The pit is 6 meters long, 5 meters across, and
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Answer:

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Volume = length x width x height

V = 6 x 5 x 3

V = 90

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