Answer:
The total number of students in a survey is 300.
Let the number of junior male(JM) be x and the number of senior males(SM) be y.
Let the number of junior female(JF) be p and the number of senior males(SF) be q.
It is given that there are 160 males, 80 junior females, 130 seniors.
Since number of males are 160. So the number of females are,
Since number of junior females is 80.
Since number of seniors are 130.
Since number of males is 160.
Therefore, the table and venn diagram is shown below.
Answer:
Problem B: x = 12; m<EFG = 48
Problem C: m<G = 60; m<J = 120
Step-by-step explanation:
Problem B.
Angles EFG and IFH are vertical angles, so they are congruent.
m<EFG = m<IFH
4x = 48
x = 12
m<EFG = m<IFH = 48
Problem C.
One angle is marked a right angle, so its measure is 90 deg.
The next angle counterclockwise is marked 30 deg.
Add these two measures together, and you get 120 deg.
<J is vertical with the angle whose measure is 120 deg, so m<J = 120 deg.
Angles G and J from a linear pair, so they are supplementary, and the sum of their measures is 180 deg.
m<G = 180 - 120 = 60
Answer:
d ≈ 5.7
Step-by-step explanation:
[Given] d² = 33
[Square root both sides] 
= 
[Solve for and cancel out the square root + square] d ≈ 5.74456
[Round to nearest tenth] d ≈ 5.7
Have a nice day!
I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)
- Heather
77 is ur answer hope this helps u
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