Question

Special segments in circles

Answer 1

If two chords intersect in a circle, then the products of the measures of the segments of the chords are equal.
I'm assuming that number up top is an 8. It's kind of blurry.

Since ten is a chord, and x is a segment of it, it can be expressed as x and 10 - x.
3(8) = x(10 - x)
$24 = 10x - x^{2}$
$x^{2} - 10x + 24 = 0$
(x - 6)(x - 4) = 0
x - 6 = 0     ....       x - 4 = 0
x = 6           ....       x = 4

4 or 6