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Alex787 [66]
2 years ago
8

Special segments in circles

Mathematics
1 answer:
pochemuha2 years ago
4 0
If two chords intersect in a circle, then the products of the measures of the segments of the chords are equal.
I'm assuming that number up top is an 8. It's kind of blurry.

Since ten is a chord, and x is a segment of it, it can be expressed as x and 10 - x.
3(8) = x(10 - x)
24 = 10x -  x^{2}
x^{2}  - 10x + 24 = 0
(x - 6)(x - 4) = 0
x - 6 = 0     ....       x - 4 = 0
x = 6           ....       x = 4

4 or 6

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AB=25 , BD=4, Solve for the radius?<br> Please help!!!!!
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9514 1404 393

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