Special segments in circles
1 answer:
If two chords intersect in a circle, then the products of the measures of the segments of the chords are equal.
I'm assuming that number up top is an 8. It's kind of blurry.
Since ten is a chord, and x is a segment of it, it can be expressed as x and 10 - x.
3(8) = x(10 - x)
(x - 6)(x - 4) = 0
x - 6 = 0 .... x - 4 = 0
x = 6 .... x = 4
4 or 6
I'm assuming that number up top is an 8. It's kind of blurry.
Since ten is a chord, and x is a segment of it, it can be expressed as x and 10 - x.
3(8) = x(10 - x)
(x - 6)(x - 4) = 0
x - 6 = 0 .... x - 4 = 0
x = 6 .... x = 4
4 or 6
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