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Alex787 [66]
2 years ago
8

Special segments in circles

Mathematics
1 answer:
pochemuha2 years ago
4 0
If two chords intersect in a circle, then the products of the measures of the segments of the chords are equal.
I'm assuming that number up top is an 8. It's kind of blurry.

Since ten is a chord, and x is a segment of it, it can be expressed as x and 10 - x.
3(8) = x(10 - x)
24 = 10x -  x^{2}
x^{2}  - 10x + 24 = 0
(x - 6)(x - 4) = 0
x - 6 = 0     ....       x - 4 = 0
x = 6           ....       x = 4

4 or 6

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Answer: 4:20 but that simplified would be 1:5

Triangles to squares

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2 years ago
Please help me with this question!!!!!!!
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A.7

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Step-by-step explanation:

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the lenght of a room is twice its breadth and thrice its height if the cost of carpeting the floor at rs 80 per sq metre is rs 9
noname [10]

Answer:

Let's define the variables:

L = length of the room

B = breadth of the room

H = height of the room.

We know that:

L = 2*B

L = 3*H

Remember that the area of a rectangle of length L and breadth B is:

A = L*B

Then the area of the floor of the room is:

A = L*B

and L = 2*B, if we replace that, we get:

A = (2*B)*B

A = 2*B^2

Now, we know that the cost of carpeting the floor is $80 per m^2

And the total cost was $9000

Then the number of square meters in the floor (thus, the area of the floor) is:

A = ($9000)/($80)  m^2

A = 112.5 m^2

With this, we can find the value of B.

A = 112.5 m^2 = 2*B^2

B = √( 112.5/2) m = 7.5 m

Then the length is:

L = 2*B = 2*7.5m = 15m

And the height is:

L = 3*H

H = L/3 = 15m/3 = 5m

Now that we know all the dimensions of the room, we need to find the area of the four walls, and the area of the ceiling (which is equal to the area of the floor 112.5 m^2)

Now, we will have two walls with an area of:

area = breadth*height = B*H = (7.5m)*(5m) = 37.5m^2

And two walls with an area of:

area = length*height = L*H = 75m^2

Then the total area of the four walls plus the ceiling is:

A' = 2*(37.5m^2) + 2*( 75m^2) + 112.5 m^2

A' = 337.5 m^2

And we know that for each m^2, the cost of plastering is $35

Then for 337.5 m^2, the cost will be 337.5 times $35

Cost = (337.5)*$35 = $11,812.50

4 0
2 years ago
PLEASE HELP 6TH GRADE MATH HOMEWORK ONE QUESTION 10 POINTS!! THANKS
Marysya12 [62]

Answer:

042

Step-by-step explanation:

- Using the first clue, we know that either 6 or 2 is in the right place. 8 is not in the combination because in the fourth clue, it states that 8 is not in the combination at all.

- Using the second clue, we know that 1 or 4 is in the combination. 6 cannot be in the combination because this rule states that when 6 is in the front position, it is wrong, but in the first clue, when 6 is in the front position, it is right. From this, we know that 2 is in the right place. The last digit of the combination is 2.

- Using the third clue, we know that only two digits are right. Since we already know 6 is not in the combination, we know that both 0 and 2 are. This rule also states that 0 is not in the middle position. Since the last position is already taken by 2, that means the first digit of the combination is 0.

All we need now is the middle digit. Let's go back to clue 2. Either 1 or 4 is in the equation. 1 is not in the middle position and 4 is not in the last position. However, if 1 is not in the middle position, 1 is not in the combination because the last and first digits are already taken. Therefore, the middle digit of the combination is 4.

5 0
3 years ago
Read 2 more answers
Match each statement with the algebraic expression that models it.
rosijanka [135]
Statement A: 

The price of a winter coat and a 20% discount
Let the price of the coat = x
20% discount = 20% of x = 0.20 × x = 0.20x
The price after the discount  = x - 0.20x = 0.80x

Statement B: 

Let the base salary be 'x'
2% increase = 2% of x = 0.02 × x = 0.02x
The salary after increase = x + 0.02x = 1.02x

Statement C:

Let the cost of groceries be 'x'
2% discount means 2% of x = 2% × x = 0.02x
The cost after discount = x - 0.02x = 0.98x

Statement D:

Let the number of students attending last year be 'x'
20% of x = 20% × x = 0.2x
The number after increase = x + 0.2x = 1.02x 

The pairs are

Statement A ⇒ Expression 2
Statement B ⇒ Expression 1
Statement C ⇒ Expression 4
Statement D ⇒ Expression 3
8 0
2 years ago
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