Special segments in circles
1 answer:
If two chords intersect in a circle, then the products of the measures of the segments of the chords are equal.
I'm assuming that number up top is an 8. It's kind of blurry.
Since ten is a chord, and x is a segment of it, it can be expressed as x and 10 - x.
3(8) = x(10 - x)
(x - 6)(x - 4) = 0
x - 6 = 0 .... x - 4 = 0
x = 6 .... x = 4
4 or 6
I'm assuming that number up top is an 8. It's kind of blurry.
Since ten is a chord, and x is a segment of it, it can be expressed as x and 10 - x.
3(8) = x(10 - x)
(x - 6)(x - 4) = 0
x - 6 = 0 .... x - 4 = 0
x = 6 .... x = 4
4 or 6
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Answer:
= 78
= 3.5
Step-by-step explanation:
First we need to find .
We can use the equation to solve for
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We can then change that equation to , since the Commutative Property of Addition says that you can have any addition in any order.
Now, we can solve the equation.
Now that we solved , we can now solve for
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Since 25 equals , we can solve the equation
.
Here is how you solve it:
Since equals 3.5, which is the simplest form, that is the answer.
Hope this helps, and please mark me brainliest! :)