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3 years ago

Write a trinomial with a GCF of 9rs^2

Mathematics

2 answers:

ikadub [295]3 years ago

5 0

18r^2s^3 + 9rs^4 + 27r^2s^4 <== there is ur trinomial

9rs^2 (2rs + s^2 + 3rs^2)

Alja [10]3 years ago

3 0

9r(3r- 2r^2s^2 - 4s^3)

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3 years ago

If f(2) = 22 – 5, then what is the value of f(2) + f(5)?

jasenka [17]

Answer:

Step-by-step explanation:

With the information of f(2) = 22-5, you can assume the equation will be f(x) = 11x-5. Using this, you can calculate f(5) by doing 11(5)-5, which is 50. 22-5 is 17, so 50+17=67

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3 years ago

Read 2 more answers

If tanA=a <br>then find sin4A-2sin2A/ sin4A+2sin2A

anygoal [31]

Answer:

The value of the given expression is

$\frac{sin4A-2sin2A}{sin4A+2sin2A}=-a^2$

Step by step Explanation:

Given that $tanA=a$

To find the value of $\frac{sin4A-2sin2A}{sin4A+2sin2A}$

Let us find the value of the expression :

$\frac{sin4A-2sin2A}{sin4A+2sin2A}=\frac{2cos2Asin2A-2sin2A}{2cos2Asin2A+2sin2A}$ ( by using the formula $sin2A=2cosAsinA$ here A=2A)

$=\frac{2sin2A(cos2A-1)}{2sin2A(cos2A+1)}$

$=\frac{(cos2A-1)}{(cos2A+1)}$

$=\frac{(-(1-cos2A))}{(1+cos2A)}$ (using $sin^2A+cos^2A=1$ here A=2A)

$=\frac{-(sin^2A+cos^2A-(cos^2A-sin^2A))}{sin^2A+cos^2A+(cos^2A-sin^2A)}$ (using $cos2A=cos^2A-sin^2A$ here A=2A)

$=\frac{-(sin^2A+cos^2A-cos^2A+sin^2A)}{sin^2A+cos^2A+(cos^2A-sin^2A)}$

$=\frac{-(sin^2A+sin^2A)}{cos^2A+cos^2A}$

$=\frac{-2sin^2A}{2cos^2A}$

$=-\frac{sin^2A}{cos^2A}$

$=-tan^2A$ ( using $tanA=\frac{sinA}{cosA}$ here A=2A )

$=-a^2$ (since tanA=a given )

Therefore $\frac{sin4A-2sin2A}{sin4A+2sin2A}=-a^2$

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3 years ago

Problem Page Alonzo will rent a car for the weekend. He can choose one of two plans. The first plan has an initial fee of $49.98

igomit [66]

You would start with the equation:Let m=number of miles

49.98+0.12m=35.98+0.17m

Then solve for m

You would then get

49.98+0.12m=35.98+0.17m
-0.12m -0.12m
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-35.98 -35.98
14 = 0.05m
---- --------
0.05 0.05

280=m

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3 years ago

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arsen [322]

I think it is 5/12 I hope it’s ok right

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