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Aneli [31]
3 years ago
8

(no links or files) Solve this equation using the quadratic formula. This question should be solved both ways. (1) Quadratic For

mula and (2) Factoring

Mathematics
1 answer:
meriva3 years ago
4 0
Quadratic formula is x = -b+ or- sq rt b^2-4ac / 2a
a=2 b=5 c=-3
-5 +or- sqrt 5^2-4(2)(-3) / 2(2)
-5 +or- sqrt 49/ 4
-5 + 7 /4 = 2/4 = 1/2
-5 - 7 /4 = -12/4 = -3

Factoring a*c is 2*-3 =-6
Factors of -6 that add to 5 are 6 and -1
Split 5x into +6x-1x
2x^2+6x-1x-3 and group
2x(x+3)-1(x+3)
(x+3)(2x-1)=0
x+3=0 gives x=-3
2x-1=0 gives x=1/2
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The value of y varies jointly with the values of x and z. When x = 4 and z = 16, the value of y is 320. When x = 8 and z = 10, t
Viktor [21]

When x is doubled, y is doubled. When z is multiplied by 5/8, so is y. The result of both changes is that y is multplied by 2·(5/8) = 5/4. The new value of y is

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_____

If you really want to, you can use the formula

... y = kxz

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4 years ago
What is the factorization of g3 – 125?
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\bf \textit{difference of cubes}
\\ \quad \\
a^3+b^3 = (a+b)(a^2-ab+b^2)\qquad
(a+b)(a^2-ab+b^2)= a^3+b^3 \\ \quad \\
a^3-b^3 = (a-b)(a^2+ab+b^2)\qquad
(a-b)(a^2+ab+b^2)= a^3-b^3 \\\\
-------------------------------\\\\
g^3-125\implies g^3-5^3\implies (g-5)(g^2+5g+5^2)
\\\\\\
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Step-by-step explanation:

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