A(n) = 2 + 9(n - 1) = 2 + 9n - 9
A(n + 1) = 2 + 9(n + 1 - 1) = 2 + 9n = (2 + 9n - 9) + 9 = A(n) + 9
Therefore, the recursive formular is A(n) = A(n - 1) + 9
Answer:
13.3 units (nearest tenth)
Step-by-step explanation:
Using the formula above, distance
![= \sqrt{ {[2 - ( - 1)]}^{2} + ( - 9 - 4)^{2} }](https://tex.z-dn.net/?f=%20%3D%20%20%5Csqrt%7B%20%7B%5B2%20-%20%28%20-%201%29%5D%7D%5E%7B2%7D%20%20%2B%20%28%20-%209%20-%204%29%5E%7B2%7D%20%7D%20)
= 13.3 units (nearest tenth)
Ok here are my interpretations for these sentences.
1.)2r+3s=13
2.)t/40=12-(1/2*s)
3.)200-3x=9
4.)1/3x+25=2x
5.)m^2-n^3=16
6.)2z=2(v+z)
Hope this helps!=)
Answer:
...
Step-by-step explanation:
,,,,,,,,,,,,,
To start this, you would have to get y by itself to have an equation you can graph. Start by subtracting 7x from both sides.
-3y= -7x+21
Next, divide both sides by -3
y = 7/3x + 7
A parallel line would have the same slope of 7/3x. Since you need to have an intercept of -1 the equation would be y = 7/3x -1
