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Bob has 4 times as many stickers as Tina. How many stickers does Bob have in terms of x?

kumpel [21]

Answer:

4x

Step-by-step explanation:

Let the number of Tina's stickers = x

So, Bob will have 4 times as many as Tina's = 4x stickers

Hope it helps you out!!

5 0

2 years ago

Hi please help me!!!!!!!!

Assoli18 [71]

Answer:

B i think

Step-by-step explanation:

6 0

2 years ago

The cost for admission to go to the amusement park is $13 plus $1.50 for each ride. If you have a total of $35.50 to spend, what

Mandarinka [93]

$35.50-$13=$22.50
$22.50/$1.50=15 rides

3 0

3 years ago

Read 2 more answers

A rectangular piece of land is to be fenced using two kinds of fencing. Two opposite sides will be fenced using standard fencing

damaskus [11]

Answer:

Therefore the dimension of the rectangular piece of land is 375 m by 250 m.

Step-by-step explanation:

Given that,

Two opposite sides of rectangular land will be fenced using standard fencing that costs $6 per m while the other two side will require heavy duty fencing that costs $9 per m.

Let the length and width of the rectangular x and y respectively.

Then total cost for fencing = $\$(2x\times 6+2y\times 9)$

=$(12x+18y)

Then,

12x+18y= 9,000

⇒ 2x+3y=1,500 [ cancel out common factor 6]

⇒3y= 1500 - 2x

$\Rightarrow y=\frac{1500-2x}{3}$ ....(1)

The area of the rectangular land is = Length × width

= xy

Let,

A=xy

Putting the value of y

$A=x.\frac{1500-2x}{3}$

$\Rightarrow A=\frac13(1500x-2x^2)$

Differentiating with respect to x

$A'=\frac13(1500-4x)$

Again differentiating with respect to x

$A''=-\frac43$

Now we have to determine the critical value of A.

For critical value set A'=0

$\frac13(1500-4x)=0$

⇒1500-4x=0

$\Rightarrow x=\frac{1500}{4}$

$\Rightarrow x=375$ m

Since, $A''|_{x=375}=-\frac43$ . at x=375 m the area of the rectangular piece of land is maximum.

From equation (1) we get when x=375

$y=\frac{1500-2\times 375}{3}$

⇒y=250 m

Therefore the dimension of the rectangular piece of land is 375 m by 250 m.

3 0

3 years ago

A small school has three foreign language classes, one in French, one in Spanish, and one in German. How many of the 34 students

serg [7]

Answer:

Statement 1 is sufficient

And the solution is 12

Statement 2 is insufficient

Step-by-step explanation:

Statement 1 : There are 27 students enrolled in the French class,and 49 students enrolled in either the French class,the Spanish class,or both of these classes.

Let S = number of Spanish-only students

F = number of French-only students

B = number of students taking both, which is the number the prompt question wants.

Given that;

S + B = 34

F + B = 27

S + F + B = 49

The equations above are from the question and statement 1.

Solving for B, we have;

(S + B) + (F + B) = 34 + 27

B + S + B + F = 61

S + B + F = 49

B + 49 = 61

B = 61 - 49 = 12

Therefore statement 1 is sufficient to give a specific and numerical solution to the question.

Statement 2: One half of the students enrolled in the Spanish class are enrolled in more than one foreign language class.

The statement 2 states that half of the students enrolled in the Spanish class are also enrolled in one foreign language but did not specify which proportion or fraction of them are enrolled in german or french therefore a specific numerical solution cannot be derived from this statement.

Hence, statement 2 is insufficient.

5 0

3 years ago