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VladimirAG [237]
4 years ago
9

14,563.98 in word form

Mathematics
1 answer:
tiny-mole [99]4 years ago
4 0
Convert 14,563.98 to words gives us fourteen thousand five hundred sixty-three and ninety-eight hundredths.
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A particular fruit's weights are normally distributed, with a mean of 733 grams and a standard deviation of 9 grams. The heavies
RoseWind [281]

Answer:

The heaviest 5% of fruits weigh more than 747.81 grams.

Step-by-step explanation:

We are given that a particular fruit's weights are normally distributed, with a mean of 733 grams and a standard deviation of 9 grams.

Let X = <u><em>weights of the fruits</em></u>

The z-score probability distribution for the normal distribution is given by;

                              Z  =  \frac{X-\mu}{\sigma}  ~ N(0,1)

where, \mu = population mean weight = 733 grams

            \sigma = standard deviation = 9 grams

Now, we have to find that heaviest 5% of fruits weigh more than how many grams, that means;

                    P(X > x) = 0.05       {where x is the required weight}

                    P( \frac{X-\mu}{\sigma} > \frac{x-733}{9} ) = 0.05

                    P(Z > \frac{x-733}{9} ) = 0.05

In the z table the critical value of z that represents the top 5% of the area is given as 1.645, that means;

                               \frac{x-733}{9}=1.645

                              {x-733}}=1.645\times 9

                              x = 733 + 14.81

                              x = 747.81 grams

Hence, the heaviest 5% of fruits weigh more than 747.81 grams.

8 0
3 years ago
Find the derivative of the function at P 0 in the direction of A. ​f(x,y,z) = 3 e^x cos(yz)​, P0 (0, 0, 0), A = - i + 2 j + 3k
Alik [6]

The derivative of f(x,y,z) at a point p_0=(x_0,y_0,z_0) in the direction of a vector \vec a=a_x\,\vec\imath+a_y\,\vec\jmath+a_z\,\vec k is

\nabla f(x_0,y_0,z_0)\cdot\dfrac{\vec a}{\|\vec a\|}

We have

f(x,y,z)=3e^x\cos(yz)\implies\nabla f(x,y,z)=3e^x\cos(yz)\,\vec\imath-3ze^x\sin(yz)\,\vec\jmath-3ye^x\sin(yz)\,\vec k

and

\vec a=-\vec\imath+2\,\vec\jmath+3\,\vec k\implies\|\vec a\|=\sqrt{(-1)^2+2^2+3^2}=\sqrt{14}

Then the derivative at p_0 in the direction of \vec a is

3\,\vec\imath\cdot\dfrac{-\vec\imath+2\,\vec\jmath+3\,\vec k}{\sqrt{14}}=-\dfrac3{\sqrt{14}}

3 0
4 years ago
7) 1 is what percent of 52.6?
katovenus [111]

Answer:

1 is what percent of 52.6? = 1.9011406844106.

Step-by-step explanation:

urm google it that is what i did

3 0
3 years ago
Read 2 more answers
Fees associated with taking out a mortgage
Valentin [98]
Closing costs is the answer to your question
6 0
4 years ago
PLEASE HELP !!!! ILL GIVE BRAINLIEST !!!
Marta_Voda [28]

Answer:

Hi it's down below! Hope it helps

Step-by-step explanation:

1) The angles are Supplementary

This is because both angles form 180°. The angle below angle "7x+9" is the same as 5x+3.  The angle above angle"5x+3" is the same as 7x+9.

2) They are both supplementary

They form 180°

3)180° = 12x+12°

4) Solving that:

180° - 12° = 12x

168° = 12x

x = 168°/12

x = 14°

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

6 0
3 years ago
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