In ∆ABC , if B= 60° , C = 3cm and A = 12cm . what is the area of ∆ABC?
1 answer:
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Answer:
15.6 cm²
Step-by-step explanation:
The area is given by the formula ...
area = 1/2ac·sin(B) = 1/2(12 cm)(3 cm)sin(60°) ≈ 15.58846 cm²
The area of ΔABC is about 15.6 cm² .
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