The perimeter of rectangle is 48 cm. Find the sides of the rectangle if one of the sides is 12 cm longer than the other.
2 answers:
Answer:
The length is 18 Cm
The Width Is 6 Cm
Step-by-step explanation:
Write an equation
so perimeter is
2L+2W=P
In this case the perimeter is 48 and one side is 12 cm longer so let’s make the unknown side W, and L as 12+w since the longer side is 12cm longer then the unknown side.
Equation:
2(12+W)+2W=48
Combine like terms and solve the equation
24+4W=48 (I distributed then combined like terms)
Subtract 24 on both sides
4W=24
Isolate the variable by dividing 4 on both sides
W=6
Check:
2(12+6)+2(6)=48?
24+12+12=48✔️
L=W+12 2L+2W=48 2(W+12)+2W=48 2W+24+2W=48 4W=48-24 4W=24 W=24/4 W=6 ANS. FOR THE WIDTH. L=6+12=18 ANS. FOR THE LENGTH. PROOF: 2*18+2*6=48 36+12=48 48=48 Hope this helps:)
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