Question

The perimeter of rectangle is 48 cm. Find the sides of the rectangle if one of the sides is 12 cm longer than the other.

Answer 1

Answer:

The length is 18 Cm

The Width Is 6 Cm

Step-by-step explanation:

Write an equation

so perimeter is

2L+2W=P

In this case the perimeter is 48 and one side is 12 cm longer so let’s make the unknown side W, and L as 12+w since the longer side is 12cm longer then the unknown side.

Equation:

2(12+W)+2W=48

Combine like terms and solve the equation

24+4W=48 (I distributed then combined like terms)

Subtract 24 on both sides

4W=24

Isolate the variable by dividing 4 on both sides

W=6

Check:

2(12+6)+2(6)=48?

24+12+12=48✔️

Answer 2

L=W+12
2L+2W=48
2(W+12)+2W=48
2W+24+2W=48
4W=48-24
4W=24
W=24/4
W=6 ANS. FOR THE WIDTH.
L=6+12=18 ANS. FOR THE LENGTH.
PROOF:
2*18+2*6=48
36+12=48
48=48

Hope this helps:)