Answer:
1. Five classes in the frequency distribution
2.The mid point of the third class is 24.5
3.The total number of frequency is 100
4.The relative frequency of the third class is (20/100=0.2)
5. We use n-1 because we are dealing with a sample data
6. The mean is 24.5
7. The value of the standard deviation is 11
Step-by-step explanation:
See attached picture for the solutions
Total 52 students.
52 - 17 = 35 students left
35 - 5 = 30 students left
30 - 2 = 28 students left
Each class has 11 students that play ONE sport, which means 22 total in 2 classes. You're on your own now! It's not that hard, I'm sure you'll figure it out.
Answer:
m = 300
Step-by-step explanation:
multiply both sides of the equation by 5
Hello!
If Bruce observes that the number of pitches a batter hits varies and is given by the function f(x)=x-11, and the batters get {4, 12, 14, 27, 42}, then Bruce threw {15, 23, 25, 38, 53} pitches. We get this solution set by adding 11 to each element in the set {4, 12, 14, 27, 42}.
Have a nice day
