Answer:
1. Option D. 15x²
2. Option C. 3
Step-by-step explanation:
1. Determination of the area of one section.
Length (L) of one section = 25x/5 = 5x
Width (W) of one section = 3x
Area (A) of one section =?
The area of one section can be obtained as follow:
Area (A) = Length (L) × Width (W)
A = L × W
A = 5x * 3x
A = 15x²
Thus, the area of one section is 15x²
2. Determination of the expressions that are equivalent to (p²)³.
We'll begin by simplifying (p²)³. This can be obtained as follow:
(p²)³ = p²*³
(p²)³ = p⁶
Next we shall compare each expression given in the question above to see which will be the same as p⁶.
p × p × p × p × p × p = p¹⁺¹⁺¹⁺¹⁺¹⁺¹
p × p × p × p × p × p = p⁶
p² × p² × p² = p²⁺²⁺²
p² × p² × p² = p⁶
p² × p³ = p²⁺³
p² × p³ = p⁵
Thus,
p² × p³ ≠ p⁶
p⁵ ≠ p⁶
p⁶ = p⁶
SUMMARY
p × p × p × p × p × p = p⁶ = (p²)³
p² × p² × p² = p⁶ = (p²)³
p⁶ = (p²)³
Therefore, 3 expressions are equivalent to (p²)³. Option C gives the correct answer to the question.
Answer: x = 143 degrees, y = 37 degrees and z = 143 degrees
Step-by-step explanation: First of all, looking at the line where x is situated,
37 + x = 180 {Sum of angles on a straight line equals 180}
Subtract 37 from both sides of the equation
x = 143
Next, looking at the line where y is situated, we observe that angle y is opposite of angle 37. Opposite angles are equal, therefore
y = 37
Alternatively, since angles x and y lie on the same line, and x has been calculated as 143, then
y + x = 180
y + 143 = 180
Subtract 143 from both sides of the equation
y = 37
Also looking at the line where angle z is situated, angle z is opposite angle x. Opposite angles are equal. Therefore z = 143.
Alternatively angle z and angle 37 lie on the same line. Therefore,
z + 37 = 180
Subtract 37 from both sides of the equation
z = 143
So all three variables are
x = 143, y = 37 and z = 143
Answer: yes!!!!!!!!!
Step-by-step explanation:
Answer:
first one is a 20 prcent decrease from x to y
and for the second one is it a 37.5 percent increase
Step-by-step explanation:
hope this helped
<u>Answer:</u>
<u>Step-by-step explanation:</u>
- Given a slope and a point on the line, you can use point slope form and then rearrage your terms into slope-intercept form
- <u>SLOPE-INTERCEPT FORM</u>:
, where "m" is your slope and "b" is your y-intercept - <u>POINT-SLOPE FORM: </u>
, where 
represents the y-coordinate of your point, 
represents the x-coordinate of your point, and 
represents the slope
