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Salsk061 [2.6K]

3 years ago

6

What is the opposite of 12? NEED HELP FAST

2 answers:

Trava [24]3 years ago

8 0

The answer would be -12

Liono4ka [1.6K]3 years ago

4 0

Answer:

-12

Step-by-step explanation:

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Two cards are drawn without replacement from a standard deck of 52 cards. What is the probability that one of the cards is red a

alukav5142 [94]

Total cards = 52
Total red cards = 26
Total black cards = 26

P(one red and one black) = P(red and then black)+ P(black and then red)
P(one red and one black) =(26/52)(26/51) + (26/52)(26/51)
P(one red and one black) = 26/51 (Answer A)

-----------------------------------------------------
Answer: 26/51 (Answer A)
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5 0

3 years ago

25 + 8 (7y - 3) + 3y

nasty-shy [4]

Answer:

59y+1

Step-by-step explanation:

25 + 8 (7y - 3) + 3y

Distribute

25+56y-24+3y

Combine like terms

59y+1

7 0

2 years ago

If f(x)=3x^2 +x-2, then f(-2)=<br><br> *12<br> *-16<br> *8<br> *32<br> help!

uysha [10]

8 is the answer

Ignore this part, Brainly wants more than 20 characters

8 0

3 years ago

What are the numbers from least to greatest based on the -7 ,4, -2, 3

Anastaziya [24]

Answer:

<em>It would be -7,-2,3,4.</em>

8 0

3 years ago

Read 2 more answers

A random sample of 23 items is drawn from a population whose standard deviation is unknown. The sample mean isx⎯ ⎯ x¯ = 840 and

gayaneshka [121]

Answer:

$(832.156, \ 847.844)$

Step-by-step explanation:

Given data :

Sample standard deviation, s = 15

Sample mean, $\overline x = 840$

n = 23

a). 98% confidence interval

$\overline x \pm t_{(n-1, \alpha /2)}. \frac{s}{\sqrt{n}}$

$$E= t_{( n-1, \alpha/2 )} \frac{s}{\sqrt n}}$

$t_{(n-1 , \alpha/2)} \frac{s}{\sqrt n}$

$t_{(n-1, a\pha/2)}=t_{(22,0.01)} = 2.508$

∴ $E = 2.508 \times \frac{15}{\sqrt{23}}$

$E = 7.844$

So, 98% CI is

$(\overline x - E, \overline x + E)$

$(840-7.844 , \ 840+7.844)$

$(832.156, \ 847.844)$

4 0

3 years ago