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3 years ago

What is the opposite of 12? NEED HELP FAST

Mathematics

2 answers:

Trava [24]3 years ago

8 0

The answer would be -12

Liono4ka [1.6K]3 years ago

4 0

Answer:

-12

Step-by-step explanation:

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Modeling Radioactive Decay In Exercise, complete the table for each radioactive isotope.

Travka [436]

Answer :

The amount after 1000 years will be, 5.19 grams.

The amount after 10000 years will be, 0.105 grams.

Step-by-step explanation :

Half-life = 1599 years

First we have to calculate the rate constant, we use the formula :

$k=\frac{0.693}{t_{1/2}}$

$k=\frac{0.693}{1599\text{ years}}$

$k=4.33\times 10^{-4}\text{ years}^{-1}$

Now we have to calculate the amount after 1000 years.

Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{a}{a-x}$

where,

k = rate constant = $4.33\times 10^{-4}\text{ years}^{-1}$

t = time passed by the sample = 1000 years

a = initial amount of the reactant = 8 g

a - x = amount left after decay process = ?

Now put all the given values in above equation, we get

$1000=\frac{2.303}{4.33\times 10^{-4}}\log\frac{8}{a-x}$

$a-x=5.19g$

Thus, the amount after 1000 years will be, 5.19 grams.

Now we have to calculate the amount after 10000 years.

Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{a}{a-x}$

where,

k = rate constant = $4.33\times 10^{-4}\text{ years}^{-1}$

t = time passed by the sample = 10000 years

a = initial amount of the reactant = 8 g

a - x = amount left after decay process = ?

Now put all the given values in above equation, we get

$10000=\frac{2.303}{4.33\times 10^{-4}}\log\frac{8}{a-x}$

$a-x=0.105g$

Thus, the amount after 10000 years will be, 0.105 grams.

4 0

3 years ago

Does anyone know the answer and how to solve?

Valentin [98]

First box should be: 2 bc of the second statement
second box (top right): 5 bc 12 students total, subtract from rest (u do this last)
third box: 1 bc all that’s leftover from first box
fourth box (bottom right) 5 bc of third statement
basically, for two way tables each box must apply/be applied to two topics. hope this helps

4 0

3 years ago

Read 2 more answers

Which of the following statements are not true?

lubasha [3.4K]

That one correct so yes um cause the app said answer must be above 20 characters

6 0

3 years ago

Suppose a random sample of n measurements is selected from a binomial population with probability of success p = .39. Given n =

Oksi-84 [34.3K]

Answer:

The answer is below

Step-by-step explanation:

a) Given that the number of sample (n) = 300, therefore since n > 30, the distribution of the sample means is going to be normally distributed.

b) The mean of the distribution of sample means (also known as the Expected value of M) is equal to the population mean μ.

$\mu_x=\mu=np=300*0.39=117$

c) The standard deviation of the distribution of sample means is called the Standard Error of M, it is given by:

$\sigma_x=\sqrt{np(1-p)} =\sqrt{300*0.39(1-0.39)} =8.44$

8 0

3 years ago

ASAP h(t)=-5t^2+5t+10<br><br> Please help me find roots and roots equation

Alex

Answer:

t = -1, 2

Step-by-step explanation:

Step 1: Define

h(t) = -5t² + 5t + 10

Step 2: Factor

h(t) = -5(t² - t - 2)

h(t) = -5(t - 2)(t + 1)

Step 3: Find roots

0 = -5(t - 2)(t + 1)

0 = (t - 2)(t + 1)

t - 2 = 0

t = 2

t + 1 = 0

t = -1

8 0

3 years ago