d = 3 , a₁₂ = 40 and S = 7775
In an arithmetic sequence the nth term and sum to n terms are
<h3>• a
= a₁ + (n-1)d</h3><h3>• S
=
[2a + (n-1)d]</h3><h3>
where d is the common difference</h3><h3>a₆ = a₁ + 5d = 22 ⇒ 7 + 5d = 22 ⇒ 5d = 15 ⇔ d = 3</h3><h3>a₁₂ = 7 + 11d = 7 +( 11× 3) = 7 + 33 = 40</h3><h3>S₁₀₀ =
[(2×7) +(99×3)</h3><h3> = 25(14 + 297) = 25(311)= 7775</h3>
Answer: add
Step-by-step explanation:
Answer:
i have to use the restroom ill answer later
Step-by-step explanation:
Answer:
Probably more expensive than the pants.
Step-by-step explanation:
Answer: $540
Step-by-step explanation:
If Milo works 40 hours for the week, he earns $12.00 per hour.
If Milo works anything over $40, he makes 1 times his normal pay which means that he is making the same amount over 40 hours as he is under 40 hours.
If he works 45 hours therefore, his pay is:
= 45 * 12
= $540