Answer:
Data at the following addresses will be as following:-
200 :- 34
201 :- 12
202 :- 78
203 :- 56
Explanation:
If there is 1 byte storage.
if the data is of 4 digits.Then we have to store it in 2 memory locations.
The first two digits will be stored at the higher byte address that is 201 and the last two digits will be stored at then lower byte address that is 200.
The case is same with the next data 5678.
At address 202 :- 78 will be stored and at address 203 :- 56 will be stored.
Answer with Explanation:
Part 1)
The given sine wave is as
The graphical representation of the wave is shown in the attached figure:
Part 2)
For a general wave equation 
'A' is defined as amplitude of the wave
is defined as phase of the wave
Upon comparing with the given wave function we observe
1) Amplitude of the given wave is 3
2) Phase of the given wave 
Answer:
a. Utilization = 0.00039
b. Throughput = 50Kbps
Explanation:
<u>Given Data:</u>
Packet Size = L = 1kb = 8000 bits
Transmission Rate = R = 1 Gbps = 1 x 10⁹ bps
RTT = 20 msec
<u>To Find </u>
a. Sender Utilization = ?
b. Throughput = ?
Solution
a. Sender Utilization
<u>As Given </u>
Packet Size = L = 8000 bits
Transmission Rate = R = 1 Gbps = 1 x 10⁹ bps
Transmission Time = L/R = 8000 bits / 1 x 10⁹ bps = 8 micro-sec
Utilization = Transmission Time / RTT + Transmission Time
= 8 micro-sec/ 20 msec + 8 micro-sec
= 0.008 sec/ 20.008 sec
Utilization = 0.00039
b. Throughput
<u>As Given </u>
Packet Size = 1kb
RTT = 20ms = 20/100 sec = 0.02 sec
So,
Throughput = Packet Size/RTT = 1kb /0.02 = 50 kbps
So, the system has 50 kbps throughput over 1 Gbps Link.
Answer:
To first create the header you will user the <h1></h1> tag
Then you will use css to align it to the center h1 {text-align: center;}
Explanation:
I would say D, Arranging for microphones.
