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son4ous [18]
2 years ago
10

Anybody else panicking while trying to finish their classes? (please say it's not just me)

Mathematics
2 answers:
emmasim [6.3K]2 years ago
6 0

Answer:

no it's me too haha

Step-by-step explanation:

galina1969 [7]2 years ago
6 0

yes currently i am taking my pre calc final and am definitely failing it

You might be interested in
Solve each equation. Show your work<br><br> 13a=-5<br> 12−b=12.5<br> -0.1=-10c
amid [387]
1) 13a=-5
Make a the subject of the formula by dividing both sides by 13(the coefficient of a)
13a/13=-5/13
Therefore a= -0.385

The second one). 12-b= 12.5
You take the 12 to the other side making b subject of the formula (-b in this case)
-b= 12.5-12
-b= 0.5
(You cannot leave b with a negative sign so you will divide both sides by -1 to cancel out the negative sign)

-b/-1= 0.5/-1
Therefore b=-0.5

The third one). -0.1= -10c
You will divide both sides by the coefficient of c(number next to c) which is -10
-0.1/-10= -10c/-10

Hence, c= 0.01
5 0
3 years ago
Past experience has indicated that the breaking strength of yarn used in manufacturing drapery material is normally distributed
vlabodo [156]

Answer:

95% two-sided confidence interval on the true mean breaking strength is (94.8cm, 99.2cm)

Step-by-step explanation:

Our sample size is 11.

The first step to solve this problem is finding our degrees of freedom, that is, the sample size subtracted by 1. So

df = 11-1 = 10.

Then, we need to subtract one by the confidence level \alpha and divide by 2. So:

\frac{1-0.95}{2} = \frac{0.05}{2} = 0.025

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 10 and 0.025 in the two-sided t-distribution table, we have T = 1.812

Now, we find the standard deviation of the sample. This is the division of the standard deviation by the square root of the sample size. So

s = \frac{4}{\sqrt{11}} = 1.2060

Now, we multiply T and s

M = Ts = 1.812*1.2060 = 2.19/tex]For the lower end of the interval, we subtract the sample mean by M. So the lower end of the interval here is[tex]L = 97 - 2.19 = 94.81 = 94.8cm

For the upper end of the interval, we add the sample mean and M. So the upper end of the interval here is

L = 97 + 2.19 = 99.19 = 99.2cm

So

95% two-sided confidence interval on the true mean breaking strength is (94.8cm, 99.2cm).

7 0
3 years ago
Please someone help please pls
mario62 [17]

Answer:

h=h= \frac{5R^{3} }{LU}

Step-by-step explanation:

1.) You must isolate the h from the equation by dividing both sides by L (or multiply by its reciprocal, which in this case, the reciprocal on L is \frac{1}{L}    .....So it would look like:

(\frac{1}{L} )*\frac{5R^{3} }{U} = \frac{L}{h}* (\frac{1}{h} )\\

2.) Simplify the equation if you need to (in this case, its not needed)

\frac{5R^3}{LU} =h

That's your answer :)

3 0
3 years ago
How do you find the surface area
WITCHER [35]

Answer:

It depends on what shape you have. Here are some formulas for different shapes.

Step-by-step explanation:

Rectangular prism: 2lw + 2lh + 2wh

Cylinder: 2 pi <em>r</em>² + 2 pi <em>rh</em>

Sphere: 4 pi <em>r</em>²

Cone: pi <em>r</em>² + pi <em>rl</em>

Square-based pyrimid: 1/2<em>lp</em> +<em>B</em>

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I hope this helps!

3 0
3 years ago
Hideki is draining a 45-gallon aquarium at a rate of 15 gallons per minute. What is the initial value of the linear function tha
kakasveta [241]
Hideki is draining a 45-gallon aquarium at a rate of 15 gallons per minute. Let's solve for the initial value of the linear function that represents thissituation.
=> 45 gallon aquarium at rate of 15 gallons per minute.
=> 45 gallon / 15 gallon = 3 minutes.
Therefore with the rate of 15 gallons per minutes, Hideki will be able to finish the 45 gallon aquarium in 3 minutes.
 
4 0
3 years ago
Read 2 more answers
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