Question

Find the equation of a line that passes through the points (2,2) and (3,6).

Answer 1

Answer:

y =4x-6

Step-by-step explanation:

first we have to find the gradient,m

m= y2-y1/x2-x1

= 6-2/3-2

= 4/1

=4

equation : y=mx+c , m=4 , (2,2) [you have only take one point either (2,2) or (3,6) is up to you ;) ]

so , sub the point and gradient into y=mx+c:

2=4(2)+c

2=8+c

2-8=c

-6=c

c=-6

In the end , y =4x-6

hope this help you!! ;)))

Answer 2

See attachment for math work and answer.