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Gekata [30.6K]
3 years ago
14

Find the equation of a line that passes through the points (2,2) and (3,6).

Mathematics
2 answers:
tester [92]3 years ago
7 0

Answer:

y =4x-6

Step-by-step explanation:

first we have to find the gradient,m

m= y2-y1/x2-x1

= 6-2/3-2

= 4/1

=4

equation : y=mx+c , m=4 , (2,2) [you have only take one point either (2,2) or (3,6) is up to you ;) ]

so , sub the point and gradient into y=mx+c:

2=4(2)+c

2=8+c

2-8=c

-6=c

c=-6

In the end , y =4x-6

hope this help you!! ;)))

densk [106]3 years ago
6 0

See attachment for math work and answer.

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subtract 4 from each side:

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add 8 to both sides:

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factor the polynomial:

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Question 51 ptsThe point (-4,-2) lies on a circle. What is the length of the radius of this circle if thecenter is located at (-
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Given,

The coordinates of the point on the circle is (-4, -2).

The coordinates of the center of the circle is (-8, -10).

Reuired

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The distance formula is,

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Substituting the value of the coordinates of the points,

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Hence,

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