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Gekata [30.6K]
3 years ago
14

Find the equation of a line that passes through the points (2,2) and (3,6).

Mathematics
2 answers:
tester [92]3 years ago
7 0

Answer:

y =4x-6

Step-by-step explanation:

first we have to find the gradient,m

m= y2-y1/x2-x1

= 6-2/3-2

= 4/1

=4

equation : y=mx+c , m=4 , (2,2) [you have only take one point either (2,2) or (3,6) is up to you ;) ]

so , sub the point and gradient into y=mx+c:

2=4(2)+c

2=8+c

2-8=c

-6=c

c=-6

In the end , y =4x-6

hope this help you!! ;)))

densk [106]3 years ago
6 0

See attachment for math work and answer.

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Name: Co
White raven [17]

Answer:

Thus last month Calvin made $414.90 from all the paintings sold at the art shows.

Step-by-step explanation:

Let us first analyse the given information in the question:

→ Small paints (lets call them s) sell for $25.80 Per Painting, thus:

  25.80s gives as the profit for s number paints sold.

→ Large paints (lets call them l) sell for $56.25 Per Painting, thus:

  56.25l gives as the profit for l number paints sold.

We also know last month he sold six large paintings and three small paintings thus from our variables above we can say:

s=3\\l=6         Eqn(1).

Thus the total profit of all paintings sold would be:

PROFIT= 25.80s+56.25l       which by pluggin in Eqn(1) values gives

PROFIT=25.80*3+56.25*6\\PROFIT=414.90

Thus last month Calvin made $414.90 from all the paintings sold at the art shows.

5 0
4 years ago
There were 60 ducks living in a pond. If the number living at the pond increased by 30%, how many ducks now live at the pond?
timama [110]

Answer:

78

Step-by-step explanation:

You take the original total: 60, and multiply it by 30 to get 1,800. You then divide 1,800 by 100 to get 18. 18 is your 30%. Now, you add the 30% to 60 getting your total number of ducks: 78.

The equation version:

\frac{a}{60} = \frac{30}{100}

It is just proportions.

3 0
2 years ago
Round to the Nearest Ten
lora16 [44]

Answer:

Step-by-step explanation:

62 to the nearest ten is 60.

6 0
3 years ago
The area of a rectangle is 63m^2 and the length of the rectangle is 11m more than twice the width. Find the length and width.
AleksandrR [38]

Answer:

width = 3.5 m

length = 18 m

Step-by-step explanation:

area = length x width

x is the width then length = 2x + 11

x(2x + 11) = 63

2x^2 + 11x - 63 = 0

The formula to solve a quadratic equation of the form ax^2 + bx + c = 0 is equal to x = [-b +/-√(b^2 - 4ac)]/2a

with a = 2

       b = 11

       c = -63

substitute in the formula

x = [-11 +/- √(11^2 - 4(2)(-63))]2(2)

x = [-11 +/- √(121 + 504)]/4

x = [-11 +/- √625]/4

x = (-11 +/- 25)/4

x1 = (-11 + 25)/4 = 14/4 = 3.5

x2 = (-11 - 25)/4 = -36/4 = -9

since width can't be a negative number, x is 3.5

length = 2x + 11 = 2(3.5) + 11 = 18

7 0
2 years ago
Whats the difference of the two expression? (3/7x+9)-(2/7x-3)
Aleksandr-060686 [28]
\left(\frac{3}{7}x+9\right)-\left(\frac{2}{7}x-3\right)\\\\=\frac{3}{7}x+9-\frac{2}{7}x-(-3)\\\\=\frac{3}{7}x+9-\frac{2}{7}x+3\\\\=(\frac{3}{7}x-\frac{2}{7}x)+(9+3)\\\\=\frac{3-2}{7}x+12\\\\=\boxed{\frac{1}{7}x+12}
4 0
4 years ago
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