Answer:
according to theorm 8 of basic geometry the answer is 6
total mass = mass of a bag of candy + mass of a chocolate bar
total mass = 80g +110g = 190g
The measure of angle EBF where he angle measures are given as m∠ABF = (8w − 6)° and m∠ABE = [2(w + 11)] is m∠EBF = 4w - 28
<h3>How to determine the
measure of
angle EBF?</h3>
The angle measures are given as
If m ∠ A B F = ( 8 w − 6 ) ° m ∠ A B E = [ 2 ( w + 11 ) ] ° m ∠ E B F
Rewrite the angle measures properly.
This is done, as follows
m∠ABF = (8w − 6)°
m∠ABE = [2(w + 11)]
The measure of angle m∠EBF is calculated as:
m∠ABF = m∠ABE + m∠EBF
Substitute the known values in the above equation
8w - 6 = 2(2w + 11) + m∠EBF
Open the brackets
8w - 6 = 4w + 22 + m∠EBF
Evaluate the like terms
m∠EBF = 4w - 28
Hence, the measure of angle EBF where he angle measures are given as m∠ABF = (8w − 6)° and m∠ABE = [2(w + 11)] is m∠EBF = 4w - 28
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Answer:
Step-by-step explanation:
Recall these rules of logs: log a + log b = log (ab), and log a^b = b log a
Then 3 log q = log q^3 and 6 log v = log v^6, and
log q^3 + 6 log v becomes log q^3 * v^6
Now rewrite this using b as the base:
log q^3 * v^6
b
40*52= 2080
34840 / 2080 = $16.75 an hour