3 pieces for each person. 38 left in total. Hope this help!
Answer:
Yes,
Step-by-step explanation:
because two sides are shown equal to each other, a and b. Also two angles are equal to each other, x and y. Once you know two angles or two sides are equal so is the third side.
Another way is SAS (side angle side). There is side a, angle y, and side b. These are shown on both triangles.
Therefore, we can conclude these two triangles are congruent.
let's bear in mind that B is the midpoint and thus it cuts a segment into two equal halves.
![\bf \underset{\leftarrow \qquad \textit{\large 10x-6}\qquad \to }{\boxed{A}\stackrel{4x+2}{\rule[0.35em]{10em}{0.25pt}} B\stackrel{\underline{4x+2}}{\rule[0.35em]{10em}{0.25pt}\boxed{C}}} \\\\\\ AC=AB+BC\implies 10x-6=(4x+2)+(4x+2)\implies 10x-6=8x+4 \\\\\\ 2x-6=4\implies 2x=10\implies x=\cfrac{10}{2}\implies x= 5 \\\\[-0.35em] ~\dotfill\\\\ AC=(4x+2)+(4x+2)\implies AC=[4(5)+2]+[4(5)+2] \\\\\\ AC=22+22\implies AC=44](https://tex.z-dn.net/?f=%5Cbf%20%5Cunderset%7B%5Cleftarrow%20%5Cqquad%20%5Ctextit%7B%5Clarge%2010x-6%7D%5Cqquad%20%5Cto%20%7D%7B%5Cboxed%7BA%7D%5Cstackrel%7B4x%2B2%7D%7B%5Crule%5B0.35em%5D%7B10em%7D%7B0.25pt%7D%7D%20B%5Cstackrel%7B%5Cunderline%7B4x%2B2%7D%7D%7B%5Crule%5B0.35em%5D%7B10em%7D%7B0.25pt%7D%5Cboxed%7BC%7D%7D%7D%20%5C%5C%5C%5C%5C%5C%20AC%3DAB%2BBC%5Cimplies%2010x-6%3D%284x%2B2%29%2B%284x%2B2%29%5Cimplies%2010x-6%3D8x%2B4%20%5C%5C%5C%5C%5C%5C%202x-6%3D4%5Cimplies%202x%3D10%5Cimplies%20x%3D%5Ccfrac%7B10%7D%7B2%7D%5Cimplies%20x%3D%205%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20AC%3D%284x%2B2%29%2B%284x%2B2%29%5Cimplies%20AC%3D%5B4%285%29%2B2%5D%2B%5B4%285%29%2B2%5D%20%5C%5C%5C%5C%5C%5C%20AC%3D22%2B22%5Cimplies%20AC%3D44)