The correct answer is: "Graph 1" ; that is, the "first graph to the left" .
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→ {among the two graphs provided as answer choices.}.
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<u>Note</u>:
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The line drawn on the graph shown on the "first graph" — (that is, the graph shown to the far left, among the two graphs provided as answer choices) — reflect the linear equation given:
" y = 6x " ;
and the line shown on the "first graph shown to the left" consists of the coordinates reflected on the table given:
" (0, 0) , (1, 6), (2, 12), (3, 18) " .
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Note that the "second graph, to the far right, is incorrect; the line provided in the "second graph" shows that:
when "x = 4" , "y = 20" .
This is incorrect; since:
Given the equation:
" y = 6x " ;
→ y = 6(4) ;
→ y = 24 ; NOT "20" ; so "Graph 2" is incorrect.
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The correct answer is: "Graph 1" ; that is, the "first graph to the left" .
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<span>Look at your table for a Z value of 1.55. The numbers on the far left column are your z values. See the 1.5 row, then move over to the 0.05 column to make it 1.55.
You'll see 0.9394.
That's the area under the normal curve from 1.55 to negative infinity.
But you wanted the area under the curve greater than 1.55.
Take 1-0.9394=0.0606.
You subtract from 1 because you know that the area under the whole curve is 1, so it gives you the area you need.</span>
Answer:
Step-by-step explanation:
V=Tr^2h
V / T = r^2 h
V / Th = r^2
√V / Th
Answer:
a I think please be right
