Using an exponential function, the inequality is given as follows:

The solution is t > 2.9, hence the tax status will change within the next 3 years.
<h3>What is an exponential function?</h3>
A decaying exponential function is modeled by:

In which:
- A(0) is the initial value.
- r is the decay rate, as a decimal.
For this problem, the parameters are given as follows:
A(0) = 9400, r = 0.143.
The population after t years is modeled by:



The tax status will change when:

Hence the inequality is:

Then:



Since both logs are negative:

t > 2.9.
The solution is t > 2.9, hence the tax status will change within the next 3 years.
More can be learned about exponential functions at brainly.com/question/25537936
#SPJ1
<span>To find StDev, we first have to find the mean of the squared differences. The differences between each score and the mean are 0,-2,2, respectively, giving squared values of 0,4,4. To find the variance, we take the sum of the three values and divide it by the number of values in the total set (3). This gives 8/3 or 2.6667. To find the population StDev, then, take the square root of the variance (2.6667), to find 1.633.</span>
Answer:
f(-5) = 37
f(-3)= 13
f(-1)= -3
f(1)= -11
f(3)= -11
Step-by-step explanation: