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2 years ago

32 x 12.71 pls help me

Mathematics

2 answers:

Igoryamba2 years ago

6 0

406.72

It is an answer I gave in a plead of help

faust18 [17]2 years ago

5 0

Answer:

406.72

Step-by-step explanation:

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Express 33 1/2% as fraction<br><br>

zzz [600]

First you have to multiply 2x33 which is 66 then you have to add 1 which is 67 so the answer would be 67/2 I don’t know about the percent sign though

8 0

3 years ago

Complete the point slope equation of the line through (-5, 7) and (-4, 0).

IgorLugansk [536]

For this case we have that by definition, the point-slope equation of a line is given by:

$y = mx + b$

Where:

m: It's the slope

b: It is the cut-off point with the y axis

We have two points:

$(x_ {1}, y_ {1}): (- 5,7)\\(x_ {2}, y_ {2}): (- 4,0)$

We found the slope:

$m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}} = \frac {0-7} {- 4 - (- 5)} = \frac {-7} {-4 + 5} = \frac {-7} {1} = - 7$

Thus, the equation is of the form:

$y = -7x + b$

We substitute one of the points and find "b":

$0 = -7 (-4) + b\\0 = 28 + b\\b = -28$

Finally, the equation is:

$y = -7x-28$

Answer:

$y = -7x-28$

5 0

3 years ago

In a string of 12 Christmas tree light bulbs, 3 are defective. The bulbs are selected at random and tested, one at a time, until

Juliette [100K]

Using the hypergeometric distribution, it is found that there is a 0.0273 = 2.73% probability that the third defective bulb is the fifth bulb tested.

In this problem, the bulbs are chosen without replacement, hence the <em>hypergeometric distribution</em> is used to solve this question.

<h3>What is the hypergeometric distribution formula?</h3>

The formula is:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

In this problem:

There are 12 bulbs, hence N = 12.

3 are defective, hence k = 3.

The third defective bulb is the fifth bulb if:

Two of the first 4 bulbs are defective, which is P(X = 2) when n = 4.

The fifth is defective, with probability of 1/8, as of the eight remaining bulbs, one will be defective.

Hence:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}$

$P(X = 2) = h(2,12,4,3) = \frac{C_{3,2}C_{9,1}}{C_{12,4}} = 0.2182$

0.2182 x 1/8 = 0.0273.

0.0273 = 2.73% probability that the third defective bulb is the fifth bulb tested.

More can be learned about the hypergeometric distribution at brainly.com/question/24826394

8 0

2 years ago

Approximately 52% of all recent births were boys. In a simple random sample of 100 recent births, 49 were boys and 51 were girls

Leni [432]

Answer:

Option A is right

Step-by-step explanation:

Given that approximately 52% of all recent births were boys. In a simple random sample of 100 recent births, 49 were boys and 51 were girls. The most likely explanation for the difference between the observed results and the expected results in this case is

A) variability due to sampling

-- True because there is a slight difference whichmay be due to sampling fluctuations.

B) bias

False because given that 100 random births selected

C) nonsampling error

False. There is no chance for systematic error here.

d) Confounding: There is no confounding variable present inchild birth since each is independent of the other

e) a sampling frame that is incomplete

False because the sampling is done correctly.

8 0

2 years ago

If the polygon is translated 2 units down and 4 units left what will the coordinates of the new image be? Use prime notation in

Luda [366]

Answer:

A’ is (3,-3)

B’ is (-1,-4)

C’ is (-1,2)

D’ is (3,1)

Step-by-step explanation: i forgot how i did this but i did it last week in math or somthing sorry if its wrong it was right for me

5 0

2 years ago