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Anuta_ua [19.1K]
3 years ago
10

Find the second and third term of the arithmetic sequence -7, _, _, -22, -27, ...

Mathematics
1 answer:
marysya [2.9K]3 years ago
5 0
Okay. The pattern here is subtracting 5, because -22 - 5 = -27. -7 - 5 = -12 And -12 - 5 = -17. -12 and -17 go in the term of the sequence, because all of the numbers together have a difference of 5. The answer is D.
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Find the area of the shape above ?
Juli2301 [7.4K]

Area of triangle = <em>A(t) </em>= 1/2(base x height)

Area of square = <em>A(s) = </em>base x height

<em>A(s) </em>= 2 x 2 = 4

<em>2(A(s))</em> = 2(1/2(2)(2) = 2(1/2(4)) = 2(2) = 4

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4 + 4 = 8

8 units² is your answer

4 0
3 years ago
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faltersainse [42]
I’m learning this to lol I think the answer is c because the absolute value is always positive right ? And the opposite of -0.89 would be positive 0.89 !
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EastWind [94]

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diamong [38]

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8 0
2 years ago
A farmer wants to fence a rectangular area of 72 square feet next to a river. Find the length and width of the rectangle which u
Arlecino [84]

Answer:

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  • 6 ft perpendicular to the river

Step-by-step explanation:

The least fence is used when half the total fence is parallel to the river. That is, the shape of the rectangle is twice as long as it is wide.

72 = W(2W)

36 = W²

6 = W . . . . . . the width perpendicular to the river

12 = 2W . . . .  the length parallel to the river

_____

<em>Development of this relation</em>

Let T represent the total length of the fence for some area A. Then if x is the length along the river, the width is y=(T-x)/2, and the area is ...

  A = xy = x(T -x)/2

Note that the equation for area is that of a parabola with zeros at x=0 and at x=T. That is, for some fence length T, the area will be a maximum at the vertex of this parabola. That vertex is located halfway between the zeros, at ...

 x = (0 +T)/2 = T/2

The corresponding area width (y) is ...

  y = (T -T/2)/2 = T/4

Equivalently, the fence length T will be a minimum for some area A when x=T/2 and y=T/4. This is the result we used above.

8 0
3 years ago
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