2 years ago

Tell whether if the following is a solution to the linear equation or not.

Mathematics

1 answer:

saul85 [17]2 years ago

8 0

Answer:

Choice 4 is correct.

Step-by-step explanation:

Hope this helps!

-Josh

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I NEED HELP 17 POINTS PLUS BRAINLIST PLEASE

Sonja [21]

Answer:

Step-by-step explanation:

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4 0

2 years ago

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Identify the equation of the circle that has its center at (-3, -4) and passes through the origin.

Allushta [10]

The equation of a circle:

$(x-h)^2+(y-k)^2=r^2$

(h, k) - a center

r - a radius

We have:

The center (-3, -4) → h = -3 and k = -4.

The radius is equal the distance between the center of the circle and the origin.

The formula of a distance between two points:

$A(x_A,\ y_A),\ B(X_B,\ y_B)\\\\d_{AB}=\sqrt{(x_B-x_A)^2+(y_B-y_A)^2}$

Substitute

$(-3,\ -4),\ (0,\ 0)\\\\d=\sqrt{(0-(-3))^2+(0-(-4))^2}=\sqrt{9+16}=\sqrt{25}=5$

therefore r = 5.

Answer:

$(x-(-3))^2+(y-(-4))^2=5^2\\\\(x+3)^2+(y+4)^2=25$

4 0

3 years ago

What does the equation 7(3x - 4) equal?

Elanso [62]

This will equal 21x - 28

6 0

2 years ago

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How do you find the x and y intercepts of x^2+x-2/x^2-3x-4?

melomori [17]

First equal the equation to f(x) or y

f(x)= (x²+x-2)÷(x²-3x-4)

To find y-intercept, x coordinates have to be 0

f(0)=(0²+0-2)÷(0²-3(0)-4)
f(0)=-2/-4
f(0)=1/2 (y-intercept)

To find x-intercept, make y=0

0=(x²+x-2)÷(x²-3x-4)
0((x²-3x-4)=(x²+x-2)
0=x²+x-2
0=(x-1)(x+2)
x-1

x-1=0
x=1

x+2=0
x=-2

The x-intercepts would be 1, -2

Hope I helped :)

3 0

3 years ago

10000p for an answer ppppppplllllleeaaaasse

frez [133]

Its b

distance between -7 and 2=9
and the difference of -7-2=-9

sooo 9 is the absolute value of -9 making it b

8 0

3 years ago