Y= 2x + 1, hope this helps
Step-by-step explanation:
log2x = 1 - log(x+4)
log2x = log10 - log(x+4)
log2x = log[10/(x+4)]
2x = 10/(x+4)
2x(x+4) = 10
2x² + 8x - 10 = 0
÷2 both sides of equation
x² + 4x - 5 = 0
(x+5)(x-1) = 0
x = -5, 1
x isn't be -5 because logA, A need to be > 0
So, x value is 1
Simultaneous Equations
2u + b = $110
4u + 3b = $268
(x2) 4u + 2b = $220
(x1) 4u + 3b = $268
<em />If both the matching coefficients are the same, we subtract equation 2 from equation 1
2b - 3b = -b
$220 - $268 = $-48
-b = -$48
b = $48
If you want to find out what a unicycle costs...
Substitute b = $48 into the first equation
2u + $48 = $110
Balance the equation, whatever happens on one side, happens on the other.
2u + $48 (-$48) = $110 (-$48)
2u = $62
2u(/2) = $62(/2)
u = $31
Answer:
a
Step-by-step explanation:
