Question

Select the solution(s) of log2x=1−log(x+4).

Answer 1

Step-by-step explanation:

log2x = 1 - log(x+4)

log2x = log10 - log(x+4)

log2x = log[10/(x+4)]

2x = 10/(x+4)

2x(x+4) = 10

2x² + 8x - 10 = 0

÷2 both sides of equation

x² + 4x - 5 = 0

(x+5)(x-1) = 0

x = -5, 1

x isn't be -5 because logA, A need to be > 0

So, x value is 1