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ycow [4]
3 years ago
8

Square root of complex number -14?

Mathematics
1 answer:
Wittaler [7]3 years ago
7 0

Answer:

square root(-14) =

3.74165739

Step-by-step explanation:

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Write the equation of the line that passes through the points (2,-6) and (6,-6).
NeTakaya

Answ

Step-by-step explanation:

Two point slope =-(-6+6)/(6-2) =0

Equation is y+6 = 0(x-2)

y+6=0

y=-6

The point is -6 at y axis which is a horizontal line.

5 0
2 years ago
Helppppppppppppppppppppppppppppppp
LuckyWell [14K]
Answer:
10√3 which is the last option

Explanation:
√30 * √10 = (30*10)^1/2
                = 300^1/2

300 = 100 * 3
Therefore:
√300 = √100 * √3 = 10√3

Hope this helps :)
5 0
2 years ago
What is the prime factorization for 50 using exponents?
galina1969 [7]

Answer:

Either way, it gives us the prime factorization for 50 that is 5 x 5 x 2. The prime factorization of 50 can be expressed using exponents as 5^2 x 2.

Step-by-step explanation:

3 0
2 years ago
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What is quotient of a number 21
stira [4]
A quotient of a number 21 is 3 and 63
Hope this helps!
8 0
3 years ago
HELP ME PLZZZ!!!! URGENT!!!​
finlep [7]

Answer:

Step-by-step explanation:

Given equation is,

x² + (p + 1)x = 5 - 2p

x² + (p + 1)x - (5 - 2p) = 0

x² + (p + 1)x + (2p - 5) = 0

Properties for the roots of a quadratic equation,

1). Quadratic equation will have two real roots, discriminant will be greater than zero. [(b² - 4ac) > 0]

2). If the equation has exactly one root, discriminant will be zero [(b² - 4ac) = 0]

3). If equation has imaginary roots, discriminant will be less than zero [(b² - 4ac) < 0].

Discriminant of the given equation = (p+1)^2-4(1)(2p-5)

For real roots,

(p+1)^2-4(1)(2p-5)>0

p² + 2p + 1 - 8p + 20 > 0

p² - 6p + 21 > 0

For all real values of 'p', given equation will be greater than zero.

5 0
3 years ago
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