Question

Which is an example of having infinitely many solutions? 1 Point 2x+8 = 2(x+8) 3x + 2(x - 2) + 6 = 5x + 2 x+7=7 X=0

Answer 1

Given:

The different equations in the options.

To find:

The equation which have infinitely many solutions.

Solution:

In option A,

$2x+8=2(x+8)$

$2x+8=2x+16$

$8=16$

This statement is false for any real value of x. So, the given equation has no solution.

In option B,

$3x+2(x-2)+6=5x+2$

$3x+2x-4+6=5x+2$

$5x+2=5x+2$

$2=2$

This statement is true for all real value of x. So, the given equation has infinitely many solutions.

In option C,

$x+7=7$

$x=7-7$

$x=0$

This equation has only one solution, i.e., x=0.

In option D,

$x=0$

This equation has only one solution, i.e., x=0.

Only equation $3x+2(x-2)+6=5x+2$ has infinitely many solutions. Therefore, the correct option is B.