Answer:
{\bold{\sqrt{2} \text { and } \sqrt{8}} are the two irrational numbers, where their product 4 is the rational number
To Find:
Two irrational numbers whose product is the rational number
Solution:
A number is said to be rational number if that number is written as fraction and an irrational number cannot be written as the ratio of any two integers.
For example, square roots.
Now, we can take 2 and 8\sqrt{2} \text { and } \sqrt{8}
2 and 8
as irrational number.
By multiplying them,
2×8=16=4\sqrt{2} \times \sqrt{8}=\sqrt{16}=4
2 ×8=16=4
We know that 4 is the rational number.
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