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yan [13]
3 years ago
7

GEOMETRY PROBLEM THAT I CAN NEVER GET

Mathematics
1 answer:
alina1380 [7]3 years ago
6 0

Answer:

Therefore the friends will have to buy 511 feet of fence (rounding up) or 510 feet of fence ( to the nearest foot).

Step-by-step explanation:

i) perimeter of rectangular yard = 319 feet

ii) perimeter of yard of friends = \frac{8}{5} \times 319 = 510.4

iii) Therefore the friends will have to buy 511 feet of fence or 510 feet of fence ( to the nearest foot).

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3 years ago
Mark A machine has two parts labeled A and B. The probability that part A works for one year is 0.8 and the probability that par
Mrrafil [7]

Answer:

0.625 = 62.5% probability that part B works for one year, given that part A works for one year.

Step-by-step explanation:

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

The probability that part A works for one year is 0.8 and the probability that part B works for one year is 0.6.

This means that P(A) = 0.8, P(B) = 0.6

The probability that at least one part works for one year is 0.9.

This means that: P(A \cup B) = 0.9

We also have that:

P(A \cup B) = P(A) + P(B) - P(A \cap B)

So

0.9 = 0.8+0.6 - P(A \cap B)

P(A \cap B) = 0.5

Calculate the probability that part B works for one year, given that part A works for one year.

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.5}{0.8} = 0.625

0.625 = 62.5% probability that part B works for one year, given that part A works for one year.

3 0
3 years ago
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Answer:C 1.2x 10^-6

Step-by-step explanation:

4 0
3 years ago
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3 years ago
Jade types 40 words in 7 minutes. Andrew types 35 words in 6 minutes. Who is the faster typist?
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May I have brainliest please? :)

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