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lisabon 2012 [21]

3 years ago

15

Susan has 3 pairs of shorts, 5 shirts, and 2 pairs of shoes to take to camp. If she wears a pair of shorts, a shirt and pair of

shoes each day, how many different outfit combinations does Susan have to choose from?

1 answer:

hjlf3 years ago

3 0

Answer:

30

Step-by-step explanation:

You might be interested in

A bus driver started her day with an empty bus. At her first stop she picked up

lidiya [134]

Answer:

12 people.

Step-by-step explanation:

Let's do this one at a time.

First stop:

0 + 11 = 11

Second stop:

11 + 5 = 16.

16 - 7 = 9.

Third stop:

9 + 5 = 14.

14 - 2 = 12.

<em>There</em><em> </em><em>were</em><em> </em><em>12</em><em> </em><em>people</em><em> </em><em>on</em><em> </em><em>the</em><em> </em><em>bus</em><em> </em><em>after</em><em> </em><em>the</em><em> </em><em>driver</em><em> </em><em>left</em><em> </em><em>the</em><em> </em><em>third</em><em> </em><em>stop</em><em>.</em>

8 0

3 years ago

Solve this equation. 4h + 6 =30

Vitek1552 [10]

First you subtract 6 from both sides to get:
4h=24
Then divide by 4:
h=6
With these problems, use the steps of either
PEDMAS, or <em></em>Please Excuse My Dear Aunt Sally.

the P stands for Parenthesis, the E for exponents, the M for multiplication, the D for division, the A for addition, and the S for subtraction

6 0

3 years ago

Read 2 more answers

If y=32, then 86y+25−78y =

FrozenT [24]

Answer:

281

Step-by-step explanation:

plug y value into expression

86(32) + 25 - 78(32)

pemdas says we must multiply first

2752 + 25 - 2496

2777 - 2496

281

4 0

3 years ago

Theres a picture help please!!!

Goryan [66]

The correct answer is A

5 0

4 years ago

adiocarbon dating of blackened grains from the site of ancient Jericho provides a date of 1315 BC ± 13 years for the fall of the

Zigmanuir [339]

Answer:

$\left(\frac{m(t)}{m_{o}} \right)_{min} \approx 0.659$ and $\left(\frac{m(t)}{m_{o}} \right)_{max} \approx 0.661$

Step-by-step explanation:

The equation of the isotope decay is:

$\frac{m(t)}{m_{o}} = e^{-\frac{t}{\tau} }$

14-Carbon has a half-life of 5568 years, the time constant of the isotope is:

$\tau = \frac{5568\,years}{\ln 2}$

$\tau \approx 8032.926\,years$

The decay time is:

$t = 1315\,years + 2007\,years \pm 13\,years$ (There is no a year 0 in chronology).

$t = 3335 \pm 13\,years$

Lastly, the relative amount is estimated by direct substitution:

$\frac{m(t)}{m_{o}} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{\mp\frac{13\,years}{8032.926\,years} }$

$\left(\frac{m(t)}{m_{o}} \right)_{min} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{-\frac{13\,years}{8032.926\,years} }$

$\left(\frac{m(t)}{m_{o}} \right)_{min} \approx 0.659$

$\left(\frac{m(t)}{m_{o}} \right)_{max} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{\frac{13\,years}{8032.926\,years} }$

$\left(\frac{m(t)}{m_{o}} \right)_{max} \approx 0.661$

4 0

3 years ago