Answer:
it is the third option because -3.2 is greater than -5.4
Step-by-step explanation:
Answer:
DOMAIN: {4,5,6,7}
RANGE: {4,4.5,5,5.5,6,6.5,7}
Step-by-step explanation:
here is proof
Mark Brainiest Please
Answer:
H0: μ = 5 versus Ha: μ < 5.
Step-by-step explanation:
Given:
μ = true average radioactivity level(picocuries per liter)
5 pCi/L = dividing line between safe and unsafe water
The recommended test here is to test the null hypothesis, H0: μ = 5 against the alternative hypothesis Ha: μ < 5.
A type I error, is an error where the null hypothesis, H0 is rejected when it is true.
We know type I error can be controlled, so safer option which is to test H0: μ = 5 vs Ha: μ < 5 is recommended.
Here, a type I error involves declaring the water is safe when it is not safe. A test which ensures that this error is highly unlikely is desirable because this is a very serious error. We prefer that the most serious error be a type I error because it can be explicitly controlled.
Answer:
$1.60
Step-by-step explanation:
Please see the attached pictures for full solution.
Answer:
D is correct
Step-by-step explanation:
Here, we want to select which of the options is correct.
The correct option is the option D
Since the die is unfair, we expect that the probability of each of the numbers turning up
will not be equal.
However, we should also expect that if we add the chances of all the numbers occurring together, then the total probability should be equal to 1. But this does not work in this case;
In this case, adding all the probabilities together, we have;
1/12 + 1/12 + 1/12 + 1/12 + 1/12 + 1/2
= 5(1/12) + 1/2 = 5/12 + 1/2 = 11/12
11/12 is not equal to 1 and thus the probability distribution cannot be correct
