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3 years ago

Algebraic expression the sum of 12 and k

1 answer:

7 0

The answer is 12+k because sum means addition and it says 12 and k therefore you and 12 and k together and the algebraic expression would be 12+k

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X - y= -4 -2x +3y =6

STatiana [176]

Answer:

x=-6, y=-2, (As a point) (-6, -2).....The point form is not necessary unless you want to solve the system (of equations) by graphing.

Step-by-step explanation:

By substitution:

x-y=-4 By adding y on both sides,

x=y-4

Now you can substitute x for the expression (y-4)

Plug the (y-4) as x in the other equation.

So -2x+3y=6 becomes

-2(y-4)+3y=6

Now solve:

-2(y-4)+3y=6 distributes out to be

-2y+8+3y=6 Now combining like terms

y+8=6 Subtract 8 on both sides to isolate the variable

y=-2

Now plug the value -2 in where the y is in any equation (preferably the easier/less complicated one) and solve for x.

So x-y=-4 becomes

x-(-2)=-4

=x+2=-4

=x=-6

3 0

2 years ago

What is another equivalent expression for -3(7 +5g)

Ilya [14]

Answer:

-21 - 15g

Step-by-step explanation:

You just have to distribute the -3 into the expression.

-3(7 + 5g) = -21 -15g

⇒

7 0

2 years ago

a taxi takes 6 hours to travel from Johannesburg to Durban at a speed of 100 km per hour. how far is it from Johannesburg to Dur

koban [17]

distance is speed multiply by time, from speed equals distance divided by time so we have 100 multiply by 6 which is 600km

4 0

2 years ago

Read 2 more answers

Please help me with 10 and 12 thank you so much

aleksandrvk [35]

10) 11
Hope this helps!
Vote me brainliest!

5 0

3 years ago

Read 2 more answers

Each of these extreme value problems has a solution with both a maximum value and a minimum value. Use Lagrange multipliers to f

tino4ka555 [31]

Answer:

The minimum value of the given function is f(0) = 0

Step-by-step explanation:

Explanation:-

Extreme value :- f(a, b) is said to be an extreme value of given function 'f' , if it is a maximum or minimum value.

i) the necessary and sufficient condition for f(x) to have a maximum or minimum at given point.

ii) find first derivative $f^{l} (x)$ and equating zero

iii) solve and find 'x' values

iv) Find second derivative $f^{ll}(x) >0$ then find the minimum value at x=a

v) Find second derivative $f^{ll}(x)$ then find the maximum value at x=a

Problem:-

Given function is f(x) = log ( x^2 +1)

step1:- find first derivative $f^{l} (x)$ and equating zero

$f^{l}(x) = \frac{1}{x^2+1} \frac{d}{dx}(x^2+1)$

$f^{l}(x) = \frac{1}{x^2+1} (2x)$ ……………(1)

$f^{l}(x) = \frac{1}{x^2+1} (2x)=0$

the point is x=0

step2:-

Again differentiating with respective to 'x', we get

$f^{ll}(x)=\frac{x^2+1(2)-2x(2x)}{(x^2+1)^2}$

on simplification , we get

$f^{ll}(x) = \frac{-2x^2+2}{(x^2+1)^2}$

put x= 0 we get $f^{ll}(0) = \frac{2}{(1)^2}$ > 0

$f^{ll}(x) >0$ then find the minimum value at x=0

Final answer:-

The minimum value of the given function is f(0) = 0

5 0

3 years ago

Algebraic expression the sum of 12 and k​

Algebraic expression the sum of 12 and k