The 32 lb. bag
because the 1 lb of the 32 lb bag costs $1.4
and 1 lb of the 15 lb bag cost $1.7
So for the first question, you basically add up all of the sides. So it would be 3y+5+3y+1+2y+6+2y+3y-4+2y+2y+8+4y-2
To simplify that combine like terms so 17y+14
For the second part of the question, it's easy algebra.
Here's your problem 17y+14=77
To solve that get the variable by itself, subtract the constant, 14, from both sides.
17y+14 -14=77 -14
17y=63
Now divide each side by the coefficient, 17
y=3.71
I might be wrong in my math somewhere, but the method is the same... you might want to check it to make sure.
<span>Which ever has 5.0 05 with a horizontal bar over the two smallest decimals.</span>
Hello:<span>
the equation is : y = ax+b
the slope is a : a×(2/3) = -1......(
perpendicular to a line : 2x-3y =7 with a slope of 2/3 because : y = (2/3)x-7/3)
a = -3/2 y=(-3/2)x+b
the line that passes through (-2, 1) : 1 =
(-3/2)(-2)+b
b = -2
<span> the equation is : y = (-3/2)x-2</span></span>
<span>$628,119.20
The formula for calculating the periodic payment on a loan is:
P = r(PV)/(1-(1+r)^(-n))
where
P = Payment
PV = Present Value
r = Interest rate per period
n = number of periods
So for this loan, assuming that payments are made monthly, the value r will be 0.05575/12 = 0.004645833, the value n will be 30*12 = 360, and PV is 592000. So let's substitute these values into the equation and calculate:
P = r(PV)/(1-(1+r)^(-n))
P = 0.004645833(592000)/(1-(1+0.004645833)^(-360))
P = 2750.333333/(1-(1.004645833)^(-360))
P = 2750.333333/(1-0.188505723)
P = 2750.333333/0.811494277
P = 3389.220861
So each payment will be $3389.22
Arnold will make a total of 360 payments, so will spend
360 * $3,389.22 = $1,220,119.20
Since his loan was for only $592,000; let's subtract that from his total payments to get the interest.
$1,220,119.20 - $592,000 = $628,119.20
Therefore his total interest is $628,119.20</span>