Answer:
vdv
Step-by-step explanation:
vfvfvdv
Answer:
Step-by-step explanation:
Can you upload another picture?
Let B = age on Ben
and age of Ishaan =I
B =4I
B = 6+I
Gives 6+I = 4I
6 = 3I
I =2 years and B = 4x2 = 8years
Age of Ishaan = 2 years
Answer:
Yes
Step-by-step explanation:
By rounding to the 10ths place, we can easily see that 6.3 is greater than 6.04. 6.3 is already rounded to the 10ths place, but 6.04 rounded to the 10ths place is 6.0.
6.3 is clearly more than 6.0, therefore 6.3 is greater than 6.04.
Answer:
We need an SRS of scores of at least 153.
Step-by-step explanation:
We have that to find our
level, that is the subtraction of 1 by the confidence interval divided by 2. So:
![\alpha = \frac{1-0.9}{2} = 0.05](https://tex.z-dn.net/?f=%5Calpha%20%3D%20%5Cfrac%7B1-0.9%7D%7B2%7D%20%3D%200.05)
Now, we have to find z in the Ztable as such z has a pvalue of
.
So it is z with a pvalue of
, so ![z = 1.645](https://tex.z-dn.net/?f=z%20%3D%201.645)
Now, find M as such
![M = z*\frac{\sigma}{\sqrt{n}}](https://tex.z-dn.net/?f=M%20%3D%20z%2A%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D)
In which
is the standard deviation of the population and n is the size of the sample.
How large an SRS of scores must you choose?
This is at least n, in which n is found when
. So
![M = z*\frac{\sigma}{\sqrt{n}}](https://tex.z-dn.net/?f=M%20%3D%20z%2A%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D)
![20 = 1.645*\frac{150}{\sqrt{n}}](https://tex.z-dn.net/?f=20%20%3D%201.645%2A%5Cfrac%7B150%7D%7B%5Csqrt%7Bn%7D%7D)
![20\sqrt{n} = 1.645*150](https://tex.z-dn.net/?f=20%5Csqrt%7Bn%7D%20%3D%201.645%2A150)
![\sqrt{n} = \frac{1.645*150}{20}](https://tex.z-dn.net/?f=%5Csqrt%7Bn%7D%20%3D%20%5Cfrac%7B1.645%2A150%7D%7B20%7D)
![\sqrt{n} = 12.3375](https://tex.z-dn.net/?f=%5Csqrt%7Bn%7D%20%3D%2012.3375)
![(\sqrt{n})^{2} = (12.3375)^{2}](https://tex.z-dn.net/?f=%28%5Csqrt%7Bn%7D%29%5E%7B2%7D%20%3D%20%2812.3375%29%5E%7B2%7D)
![n = 152.2](https://tex.z-dn.net/?f=n%20%3D%20152.2)
Rounding to the next whole number, 153
We need an SRS of scores of at least 153.