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Elanso [62]
2 years ago
9

Find the value of m​

Mathematics
1 answer:
Anuta_ua [19.1K]2 years ago
4 0

fond the value of m en libret

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Find a formula for the sum S of the solutions of the quadratic equation ax²+bx+c=0 .
Deffense [45]

Answer:

S = -\frac{b}{a}

Step-by-step explanation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = (x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}

x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}

\bigtriangleup = b^{2} - 4ac

In this problem, the sum S of the solutions of a quadratic equation is:

S = x_{1} + x_{2}

So

S = \frac{-b + \sqrt{\bigtriangleup}}{2*a} + \frac{-b - \sqrt{\bigtriangleup}}{2*a}

They have the same denominators, so we can keep the denominators and sum the numerators.

S = \frac{-b + \sqrt{\bigtriangleup} - b - \sqrt{\bigtriangleup}}{2a}

S = \frac{-2b}{2a}

S = -\frac{b}{a}

8 0
3 years ago
What two numbers multiply to give you a -90 and add up to gives you one
just olya [345]
10 and (-9)

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5 0
2 years ago
Please help asap. need this done tomorrow​
egoroff_w [7]

Answer: (EF) ax+by+c=0

do you know normal vector? vector EF=(7;3) --> normal vector (-3;7)

---> (EF)-3x+7y+c=0. because (EF) passes through E(1;-3) so -3.1+7.(-3)+c=0 ---> c=24

(EF) -3x+7y+24=0

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Did anyone get the answer I think its A, and D
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3 years ago
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