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REY [17]
3 years ago
10

Need a quick answer please

Mathematics
1 answer:
Over [174]3 years ago
5 0

Answer:

39

Step-by-step explanation:

6x-15+3x+6=90

Simplify: 9x-9=90

9x=99

x=11

3(11)+6

33+6

<H= 39

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Find the minimum value of c = 4x + 3y
shutvik [7]

Step-by-step explanation:

C=4x+3y Constraints: x is greater than or equal to 0 2x + 3y is greater than or equal to 6 3x - 2y is less than or equal to 9 x + 5y is less than or equal to 20

8 0
2 years ago
Question in the image below:
horrorfan [7]

Answer:

x = 5/33 or 0.151515151

Step-by-step explanation:

7(-6x-2) = 8(3x-4)

step 1: simplify the equation.

-42x - 14 = 24x - 4

step 2: isolate the variable (using the balance method).

-42x - 14 + 14 = 24x - 4 + 14

-42x = 24x + 10

-42x - 24x = 24x - 24x + 10

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step 3: solve for x.

x = 10 ÷ -66

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4 0
2 years ago
Sierra’s ice cream shop made $45 before she had to close early when the power went out. She realized she lost Two-thirds of a do
lozanna [386]

Answer:

Sierra's profit was $41.

Step-by-step explanation:

Sierra realized she lost two-third of a dollar each hour when the shop was closed.

The expression that models this situation is,  ............. (1)

Now, we have to calculate Sierra's profit if the shop was closed for 6 hours.

So, putting h = 6 hours in the equation (1) we get,

dollars.

So, Sierra's profit was $41. (Answer)

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
I don’t understand this can someone explain this to me?
olga2289 [7]

Answer:

16x 144

Step-by-step explanation:

4x times 4x then 12 times 12 than that is you answer beacons you can ad 12 and 4x because  the 12 has no x

7 0
3 years ago
A prticular type of tennis racket comes in a midsize versionand an oversize version. sixty percent of all customers at acertain
svetlana [45]

Answer:

a) P(x≥6)=0.633

b) P(4≤x≤8)=0.8989 (one standard deviation from the mean).

c) P(x≤7)=0.8328

Step-by-step explanation:

a) We can model this a binomial experiment. The probability of success p is the proportion of customers that prefer the oversize version (p=0.60).

The number of trials is n=10, as they select 10 randomly customers.

We have to calculate the probability that at least 6 out of 10 prefer the oversize version.

This can be calculated using the binomial expression:

P(x\geq6)=\sum_{k=6}^{10}P(k)=P(6)+P(7)+P(8)+P(9)+P(10)\\\\\\P(x=6) = \binom{10}{6} p^{6}q^{4}=210*0.0467*0.0256=0.2508\\\\P(x=7) = \binom{10}{7} p^{7}q^{3}=120*0.028*0.064=0.215\\\\P(x=8) = \binom{10}{8} p^{8}q^{2}=45*0.0168*0.16=0.1209\\\\P(x=9) = \binom{10}{9} p^{9}q^{1}=10*0.0101*0.4=0.0403\\\\P(x=10) = \binom{10}{10} p^{10}q^{0}=1*0.006*1=0.006\\\\\\P(x\geq6)=0.2508+0.215+0.1209+0.0403+0.006=0.633

b) We first have to calculate the standard deviation from the mean of the binomial distribution. This is expressed as:

\sigma=\sqrt{np(1-p)}=\sqrt{10*0.6*0.4}=\sqrt{2.4}=1.55

The mean of this distribution is:

\mu=np=10*0.6=6

As this is a discrete distribution, we have to use integer values for the random variable. We will approximate both values for the bound of the interval.

LL=\mu-\sigma=6-1.55=4.45\approx4\\\\UL=\mu+\sigma=6+1.55=7.55\approx8

The probability of having between 4 and 8 customers choosing the oversize version is:

P(4\leq x\leq 8)=\sum_{k=4}^8P(k)=P(4)+P(5)+P(6)+P(7)+P(8)\\\\\\P(x=4) = \binom{10}{4} p^{4}q^{6}=210*0.1296*0.0041=0.1115\\\\P(x=5) = \binom{10}{5} p^{5}q^{5}=252*0.0778*0.0102=0.2007\\\\P(x=6) = \binom{10}{6} p^{6}q^{4}=210*0.0467*0.0256=0.2508\\\\P(x=7) = \binom{10}{7} p^{7}q^{3}=120*0.028*0.064=0.215\\\\P(x=8) = \binom{10}{8} p^{8}q^{2}=45*0.0168*0.16=0.1209\\\\\\P(4\leq x\leq 8)=0.1115+0.2007+0.2508+0.215+0.1209=0.8989

c. The probability that all of the next ten customers who want this racket can get the version they want from current stock means that at most 7 customers pick the oversize version.

Then, we have to calculate P(x≤7). We will, for simplicity, calculate this probability substracting P(x>7) from 1.

P(x\leq7)=1-\sum_{k=8}^{10}P(k)=1-(P(8)+P(9)+P(10))\\\\\\P(x=8) = \binom{10}{8} p^{8}q^{2}=45*0.0168*0.16=0.1209\\\\P(x=9) = \binom{10}{9} p^{9}q^{1}=10*0.0101*0.4=0.0403\\\\P(x=10) = \binom{10}{10} p^{10}q^{0}=1*0.006*1=0.006\\\\\\P(x\leq 7)=1-(0.1209+0.0403+0.006)=1-0.1672=0.8328

7 0
3 years ago
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