Give the Solution to the System of

Find x. A. 21√2 B. 7 C. 21√3 over 2 D. 21√2 over 2

kkurt [141]

Answer:

D

Step-by-step explanation:

for you to find x you first have to find the adjacent of the 45° angle you can do that by using the other triangle.using the sin ratio

sin60=opposite/hypotenuse

sin60=a/7√3

a=10.5

then after you have found the adjacent you can use the cos ratio

cos45=adjacent/hypotenuse

cos45=10.5/x

cos45x/cos45=10.5/cos45

x=14.849

which is the same as 21√2 over 2

I hope this helps

5 0

3 years ago

Read 2 more answers

What is the solution of the system? Use substitution.

trasher [3.6K]

Hi

4x-y=5

3x-7=2

We need to solve 3x-7=2 for x

Let's start by adding 7 to both sides

3x-7+7=2+7

3x=9

Now just divide both sides by 3 so we can find the value for x

3x/3=9/3

x=3

Now substitute 3 for x in 4x-y=5

4x-y=5

(4)(3)-y=5

-y+12=5

Now add -12

-y=12-12=5-12

-y=-7

Divide both sides by -1 so we can eliminate the negative sign

-y/-1=-7/-1

y=3

The answer is A

(3,7)

I hope that's help:0

6 0

3 years ago

How to find an equation for a line through two given points?

xz_007 [3.2K]

Answer:

The equation of the line is: $y = 0.6x + 0.6$

Step-by-step explanation:

Equation of a line:

The equation of a line has the following format:

$y = mx + b$

In which m is the slope and b is the y-intercept.

Two points:

We have these following two points in this exercise:

x = -6, y = -3, so (-6,-3)

x = 4, y = 3, so (4,3)

Finding the slope:

Given two points, the slope is given by the change in y divided by the change in x.

Change in y: 3 - (-3) = 3 + 3 = 6

Change in x: 4 - (-6) = 4 + 6 = 10

So

$m = \frac{6}{10} = 0.6$

Then

$y = 0.6x + b$

Finding b:

We replace one of the points in the equation to find b. I will use (4,3).

$y = 0.6x + b$

$3 = 0.6*4 + b$

$2.4 + b = 3$

$b = 0.6$

The equation of the line is: $y = 0.6x + 0.6$

4 0

3 years ago

PLEASE HELP ME FOR BRAINLIESTTT!!!

lyudmila [28]

Answer:

Sorry I cant help But I think that well I dont know but if you have any other questions i can help you with I can.

Step-by-step explanation:

4 0

2 years ago

Find the length of the tangent segment AB to the circles centered at O and O' whose radii are a and b respectively when the circ

bixtya [17]

Answer:

$AB=2\sqrt{ab}$

Step-by-step explanation:

From figure,

$OA=a, \quad \quad O'B=b\\\Rightarrow OO'= (a+b) \quad \quad \text{and}\quad OD=(a-b)$

In triangle $OO'D$

$(OO')^2=(OD)^2+(O' D)^2$

$\Rightarrow (a+b)^2=(a-b)^2+(O' D)^2\\\Rightarrow a^2+b^2+2ab-a^2-b^2+2ab=(O' D)^2\\\Rightarrow 4ab=(O' D)^2\\\Rightarrow O'D=2\sqrt{ab} \\\Rightarrow O' D=2\sqrt{ab}=AB \quad \quad [\because O' DAB\;\; \text{is a rectangle.}]$

Hence, $AB=2\sqrt{ab}$

6 0

3 years ago