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mars1129 [50]
3 years ago
13

The hour, minute, and second hands on a clock are 0.25 m , 0.31 m , and 0.34 m long, respectively.

Physics
1 answer:
sp2606 [1]3 years ago
6 0

In 1 hour, the hour hand sweeps across 1/12 of the clock's face. In 40 min, the hour hand travels (40 min)/(60 min) = 2/3 of the path it covers in an hour, so a total of 1/12 × 2/3 = 1/18 of the clock's face. This hand traces out a circle with radius 0.25 m, so in 40 min its tip traces out 1/18 of this circle's radius, or

1/18 × 2<em>π</em> (0.25 m) ≈ 0.087 m

The minute hand traverses (40 min)/(60 min) = 2/3 of the clock's face, so it traces out 2/3 of the circumference of a circle with radius 0.31 m:

2/3 × 2<em>π</em> (0.31 m) ≈ 1.3 m

The second hand completes 1 revolution each minute, so in 40 min it would fully trace the circumference of a circle with radius 0.34 m a total of 40 times, so it covers a distance of

40 × 2<em>π</em> (0.34 m) ≈ 85 m

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You have two identical capacitors and an external potential source.a) Compare the total energy stored in the capacitors when the
AnnyKZ [126]

Correct answer would be C.

8 0
3 years ago
The blood pressure at your heart is approximately 100 mm Hg. As blood is pumped from the left ventricle of your heart, it flows
RoseWind [281]

Answer:

The correct option is c. 75 for this question

Explanation:

The correct option is c. 75 for this question:

Let's see how.

Continuity Equation is given as:

AcVc = AaVa

Where,

Aa = Area of Aorta

Ac = Area of the capillary

Va = Fluid speed in Aorta

Vc = Fluid speed in Capillary

So,

Assuming the fluid is the ideal one/

\pi/4 Dc^{2} Vc= \pi/4 Da^{2} Va

Dc^{2} Vc= Da^{2} Va

Dc = Da x \sqrt{\frac{Va}{Vc} }

Dc = 2.5 cm x \sqrt{\frac{60 cm}{0.07 cm } }

Dc = 73.192 cm

Dc = 75 approximately

Hence, the diameter of the capillary = 75 cm approximately  

3 0
3 years ago
Assume that the average mass of each of the approximately 1 billion people in China is 55 kg.Assume that they all gather in one
Harman [31]

Answer: 5.9(10)^{-8} m

Explanation:

The equation to calculate the center of mass C_{M} of a particle system is:

C_{M}=\frac{m_{1}r_{1}+m_{1}r_{1}+...+m_{n}r_{n}}{m_{1}+m_{2}+...+m_{n}}

In this case we can arrange for one dimension, assuming the geometric center of the Earth and the ladder are on a line, and assuming original center of mass located at the Earth's geometric center:

C_{M}=\frac{m_{E}(0 m) + m_{p} r_{E-p}}{m_{E}+m_{p}}

Where:

m_{E}=5.9(10)^{24} kg is the mass of the Earth

m_{p}=55(10)^{9} kg is the mass of 1 billion people

r_{E}=6371000 m is the radius of the Earth

r_{E-p}=6371000 m- 2m=6370998 m is the distance between the center of the Earth and the position of the people (2 m above the Earth's surface)

C_{M}=\frac{m_{p}55(10)^{9} kg (6370998 m)}{5.9(10)^{24} kg+55(10)^{9} kg}

C_{M}=5.9(10)^{-8} m This is the displacement of Earth's center of mass from the original center.

8 0
3 years ago
The Golden Gate Bridge in San Francisco has a main span of length 1.28 km, one of the longest in the world. Imagine that a steel
Valentin [98]

Answer:

361.46 N

Explanation:

\alpha = Coefficient of thermal expansion = 11\times 10^{-6}\ /^{\circ}C

Y = Young's modulus for steel = 20\times 10^{10}\ Pa

A = Area = 3.1\times 10^{-6}\ m^2

L_0 = Original length = 1.28 km

\Delta T = Change in temperature = 45-(-10)

Length contraction is given by

\Delta L=\alpha L_0\Delta T

Also,

\Delta L=\dfrac{L_0T}{YA}

\alpha L_0\Delta T=\dfrac{L_0T}{YA}\\\Rightarrow T=\alpha \Delta TYA\\\Rightarrow T=11\times 10^{-6}\times (43-(-10))\times 20\times 10^{10} \times 3.1\times 10^{-6}\\\Rightarrow T=361.46\ N

The tension in the wire is 361.46 N

4 0
3 years ago
Subject: Science
notka56 [123]
Because if you're not truthful about your results then the science community will never believe anything else you publish even if it's true.
7 0
3 years ago
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