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Dmitry_Shevchenko [17]
3 years ago
8

You have two identical capacitors and an external potential source.a) Compare the total energy stored in the capacitors when the

y are connected to the applied potential in series and in parallel.U(parallel)/U(series) =?b) Compare the maximum amount of charge stored in each case.Q(parallel)/Q(series) =?c) Energy storage in a capacitor can be limited by the maximum electric field between the plates. What is the ratio of the electric field for the series and parallel combinations?E(parallel)/E(series) =?
Physics
1 answer:
AnnyKZ [126]3 years ago
8 0

Correct answer would be C.

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A 62 kg skier is moving at 6.5 m/s on frictionless horizontal snow-covered plateau when she encounters a rough patch 3.50 m long
Degger [83]

Answer:

(A). The work done by friction in crossing the patch is -637.98 J.

(B). The speed of skier is 10.57 m/s.

Explanation:

Given that,

Mass of skier = 62 kg

Speed = 6.5 m/s

Length = 3.50 m

Coefficient kinetic friction = 0.30

Height = 2.5 m

(A) we need to calculate the work done by friction in crossing the patch

Using formula of work done

W=-\mu mg\times l

Put the value into the formula

W=-0.30\times62\times9.8\times3.50

W=-637.98\ J

The work done by friction in crossing the patch is -637.98 J.

(B) we need to calculate the speed of skier

Using conservation of energy

K.E_{i}+U_{i}-W_{friction}=K.E_{f}+U_{f}

\dfrac{1}{2}mv_{1}^2+mgh-\mu mgl=\dfrac{1}{2}mv_{2}^2+U_{f}

Final potential energy is zero

So, \dfrac{1}{2}mv_{1}^2+mgh-\mu mgl=\dfrac{1}{2}mv_{2}^2

\dfrac{1}{2}v_{2}^2=\dfrac{1}{2}v_{1}^2+gh-\mu gl

Put the value into the formula

\dfrac{1}{2}v_{2}^2=\dfrac{1}{2}\times6.5^2+9.8\times2.5+0.30\times9.8\times3.50

v_{2}=\sqrt{2\times55.915}

v_{2}=10.57\ m/s

The speed of skier is 10.57 m/s.

Hence,  (A).The work done by friction in crossing the patch is -637.98 J.

(B).The speed of skier is 10.57 m/s.

6 0
3 years ago
The diagram below shows the velocity vectors for two cars that are moving relative to each other.
scoundrel [369]

Answer:

The answer is "5 \ \frac{m}{s} \ west"

Explanation:

\to \vec{V_1} = (25 \frac{m}{s}) (\hat{-i})\\\\\to  \vec{V_2} = (20 \frac{m}{s}) (\hat{-i})\\\\

velocity of car | respect to car :

\to \vec{V_{12}} = \vec{V_1} - \vec{V_2}\\\\

          =\vec{-25} \hat{i}+ \vec{20} \hat{i}\\\\= 5 \ \frac{m}{s} \ west

7 0
3 years ago
When describing electromagnetic radiation, there is a(n) _____________ relationship between wavelength and frequency and the gre
disa [49]

Its actually C. I did the question on USA test prep and it said the correct answer was C.


6 0
3 years ago
Read 2 more answers
When a second student joins the first, the height difference between the liquid levels in the right and left pistons is 40 cm .
vlada-n [284]

Answer:

m = 56.5 kg

Explanation:

Since the addition of mass on one piston caused a change in pressure head at the other. Diameter of the piston calculated is used as 0.46 m

Δm*g / Area = p * g * Δh   ..... Eq1

m = \frac{p*h*A}{g}

m = \frac{850 * 0.4 * pi*0.46^2}{4*9.81}\\\\m= 56.5 kg

8 0
2 years ago
A boat produced water waves of frequency 4 Hz and wavelength 2m, if it reached the shore after 2 seconds how far is the boat fro
kap26 [50]

Answer:

S = 16 m

Explanation:

Given that

The frequency of the water waves, f = 4 Hz

The wavelength of the water waves, λ = 2 m

The time the waves reached the shore, t = 2 s

The relation between the velocity, wavelength, and the frequency of the wave is given by the relation,

                                           v = f λ    m/s

Substituting the given values in the above equation,

                                           v = 4 x 2

                                              = 8 m/s

The velocity of the water waves is v = 8 m/s

The distance between the shore and boat is given by

                                            s = v x t

                                               = 8 x 2

                                               = 16 m

Hence, the distance between the boat and the shore is, s = 16 m

7 0
3 years ago
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