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Dmitry_Shevchenko [17]
3 years ago
8

You have two identical capacitors and an external potential source.a) Compare the total energy stored in the capacitors when the

y are connected to the applied potential in series and in parallel.U(parallel)/U(series) =?b) Compare the maximum amount of charge stored in each case.Q(parallel)/Q(series) =?c) Energy storage in a capacitor can be limited by the maximum electric field between the plates. What is the ratio of the electric field for the series and parallel combinations?E(parallel)/E(series) =?
Physics
1 answer:
AnnyKZ [126]3 years ago
8 0

Correct answer would be C.

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Two parallel plates have equal and opposite charges. When the space between the plates is evacuated, the electric field is E= 3.
svetlana [45]

Explanation:

The given data is as follows.

     Electric field between plates without dielectric, E_{1} = 3.50 \times 10^{5} V/m

   Electric field between the plates with dielectric, E_{2} = 2.40 \times 10^{5} V/m.

  Permittivity of free space, \epsilon_{o} = 8.85 \times 10^{-12} C^{2}/Nm^{2}

Now, we will determine the charge density as follows.

            \sigma_{i} = \epsilon_{o}(E_{1} - E_{2})

                 = 8.85 \times 10^{-12} \times (3.50 \times 10^{5} - 2.40 \times 10^{5})

                 = 9.735 \times 10^{-7} C/m^{2}

Thus, we can conclude that the charge density on each surface of the dielectric is 9.735 \times 10^{-7} C/m^{2}.

6 0
3 years ago
In addition to stand-alone discussion boards, all of these sites include discussion boards as part of their features except: ​
adell [148]

Answer:

A. Linkedln

Explanation:

In addition to stand-alone discussion boards, all of these sites include discussion boards as part of their features except: ​

A. Linkedln

All other application in addition to stand-alone Google, Yahoo, Microsoft, etc. include discussion board.

8 0
3 years ago
(a) Find the frequency of revolution of an electron with an energy of 114 eV in a uniform magnetic field of magnitude 46.7 µT. (
stira [4]

Answer:

(a)  1.3 x 10^6 Hz

(b) 76.73 cm

Explanation:

(a)

the formula for the frequency is given by

f = B q / 2 π m

where, B be the strength of magnetic field, q be the charge on one electron, m is the mass of one electron.

B = 46.7 micro tesla = 46.7 x 10^-6 T

q = 1.6 x 10^-19 C

m = 9.1 x 10^-31 kg

f = (46.7 x 10^-6 x 1.6 x 10^-19) / (2 x 3.14 x 9.1 x 10^-31) = 1.3 x 10^6 Hz

(b) K = 114 eV = 114 x 1.6 x 10^-19 J = 182.4 x 10^-19 J

K = 1/2 mv^2

182.4 x 10^-19 = 0.5 x 9.1 x 10^-31 x v^2

v = 6.3 x 10^6 m/s

r = m v / B q

Where, r be the radius of circular path

r = (9.1 x 10^-31 x 6.3 x 10^6) / (46.7 x 10^-6 x 1.6 x 10^-19)

r = 0.7673 m = 76.73 cm  

5 0
3 years ago
A child does 350J of work while pulling a box from the ground up to his tree house with a rope. The tree house is 5.2 m above th
Advocard [28]

I think the answer to that questions is B.

3 0
3 years ago
A MEMS-based accelerometer has a mass of m = 2 grams, an equivalent spring constant of k = 5 N/m, and an equivalent damping coef
pychu [463]

Answer:

The natural frequency = 50 rad/s = 7.96 Hz

Damping ratio = 0.5

Explanation:

The natural frequency is calculated in this manner

w = √(k/m)

k = spring constant = 5 N/m

m = mass = 2 g = 0.002 kg

w = √(5/0.002) = 50 rad/s

w = 2πf

50 = 2πf

f = 50/(2π) = 7.96 Hz

Damping ratio = c/[2√(mk)] = 0.1/(2 × √(5 × 0.002)) = 0.5

5 0
3 years ago
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