Answer:
Q1
<u>The exponential growth model for frogs:</u>
F- number of frogs, x- number of years, 1.22 - growth factor
<u>Calculations</u>:
- F(5) = 100(1.22)⁵ = 270
- a) F(10) = 100(1.22)¹⁰ = 730
- b) F(20) = 100(1.22)²⁰ = 5335
<em>All numbers rounded </em>
Q2
<u>The exponential growth model for bacteria:</u>
B- number of bacteria, x- number of hours, 1.8 - growth factor
<u>Calculations:</u>
- a) B(5) = 10(1.8)⁵ = 189
- b) B(24) = 10(1.8)²⁴ = 13382588
- c) B(168) = 10(1.8)¹⁶⁸ = 7.68 * 10⁴³
<em>All numbers rounded </em>
Q3.
<u>The exponential growth model for fish:</u>
F- number of fish, x- number of months, 1.02 - growth factor
<u>Calculations:</u>
- a) F(12) = 821(1.02)¹² = 1041
- b) F(120) = 821(1.02)¹²⁰ = 8838
<em>All numbers rounded </em>
Answer:
The population can be greater than 6,100 but less than 6,300, and thus, we cannot determine if the population of Farmersville will be greater than 6,300 in 2012.
Step-by-step explanation:
Inequality for the population of Farmsville:
The inequality for the population of Farmsville in x years after 2010 is given by:
Will the population of Farmersville be greater than 6,300 in 2012?
2012 is 2012-2010 = 2 years after 2010, so we have to find y(2).
The population can be greater than 6,100 but less than 6,300, and thus, we cannot determine if the population of Farmersville will be greater than 6,300 in 2012.
Answer:
two blocks east
Step-by-step explanation:
the north and south cancel out and then 3 blocks east - 1 block west = 2 blocks east
Answer:
yes
Step-by-step explanation:
80 ÷ 20 = 4
56 ÷ 14 = 4
yes they are equivalent
Answer:
theta =36.45268177
Step-by-step explanation:
Since this is a right triangle, we can use trig functions
cos theta = adj/ hyp
cos theta = 74/92
Taking the inverse cos of each side
cos^-1 ( cos theta) = cos^-1 (74/92)
theta =36.45268177
