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3 years ago

Evaluate n^2 -m. If you n=-5 and m=3

Mathematics

2 answers:

Roman55 [17]3 years ago

3 0

Answer:

Step-by-step explanation:

n² - m =

-5² - 3 =

25 - 3 = 22

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katovenus [111]3 years ago

3 0

Answer:

Step-by-step explanation:

(-5)^2- 3

two negatives make a positive which would be 25 then minus the 3

=25-3

then you get your total

=22

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HELP!!! Simplify cos^2 0 -1/ 4sin^2 0?

Shkiper50 [21]

We need to simpify the given expression. The given expression to us is ,

Given Expression :-

$\sf\implies \dfrac{ cos^2\theta -1}{4 \ sin^2\theta }$

Using Identity :-

$\sf\implies \red{ sin^2\theta + cos^2\theta = 1}$

So that :-

$\sf\implies - sin^2\theta = cos^2\theta -1$

We have :-

$\sf\implies \dfrac{ cos^2\theta -1}{4 \ sin^2\theta } \\\\\sf\implies\dfrac{ - sin^2\theta}{4sin^2\theta}=\boxed{\sf -\dfrac{1}{4}}$

Hence the required answer is -1/4. 

5 0

3 years ago

An object falls from a position of rest and

kumpel [21]

Answer:

About 4.1323 meters.

Step-by-step explanation:

We can use the following kinematic equations:

$\displaystyle v_f = v_0 + at \text{ and } \Delta d = v_0 t + \frac{1}{2} at^2$

We want to determine the distance the object has dropped after falling from rest and reaching an instantenous speed of 9 m/s.

We are given that the acceleration due to gravity is 9.8 m/s².

Using this fact and the first equation, find the time for which it took the object to reach 9 m/s. Note that the initial velocity is 0 m/s since the object started from rest.

$\displaystyle \begin{aligned} v_f = v_0 + at \\ \\ (9\text{ m/s}) & = (0\text{ m/s}) + (9.8\text{ m/s$^2$})t \\ \\ 9\text{ m/s} & = (9.8 \text{ m/s$^2$})t \\ \\ t &\approx0.9184 \text{ s} \end{aligned}$

To find how far the object dropped, we can use the second equation:

$\displaystyle\begin{aligned} \Delta d & = v_0 t + \frac{1}{2} at^2 \\ \\ & = (0\text{ m/s})(0.9184 \text{ s}) + \frac{1}{2}(9.8 \text{ m/s$^2$})(0.9184 \text{ s})^2 \\ \\ & = 4.1323 \text{ m} \end{aligned}$

In conclusion, the object would have dropped about 4.1323 meters.

6 0

3 years ago

Einsteinium-

Natalija [7]

Answer:

$S(t)=450(2/3)^t$

Explanation:

The question is "Einstenium-253 is an element that loses about 2/3 of its mass every month. A sample of einstenium-253 has 450 grams. Write a function that gives the sample's mass in grams, S(t) from today".

Since einstenium-253 loses about 2/3 of its mass every month, you can model the amount of sample by an exponential decay function, which is a geometric progression with a growing factor less than 1.

The general form of an exponential decay function is:

$y=A_0r^t$

Where:

A₀ is the initial value
r is the growing or decaying factor
t is the time
y is the value of the function at time t.

In this case, you have:

A₀ = 450
r = 2/3
t = t
y = S(t)

Now you can replace the values in the model and will obtain:

$S(t)=450(2/3)^t$

4 0

3 years ago

Please help me it's done in 4 mins I beg you

lesya692 [45]

Answer:

the slope rise/run = 4/6

4 0

3 years ago

Which transformations could have occurred to

Semmy [17]

Step-by-step explanation:

•a reflection and a dilation

8 0

3 years ago