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NemiM [27]
3 years ago
10

Evaluate n^2 -m. If you n=-5 and m=3

Mathematics
2 answers:
Roman55 [17]3 years ago
3 0

Answer:

22

Step-by-step explanation:

n² - m =

-5² - 3 =

25 - 3 = 22

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

katovenus [111]3 years ago
3 0

Answer:

22

Step-by-step explanation:

(-5)^2- 3

two negatives make a positive which would be 25 then minus the 3

=25-3

then you get your total

=22

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HELP!!! Simplify cos^2 0 -1/ 4sin^2 0?
Shkiper50 [21]

We need to simpify the given expression. The given expression to us is ,

<u>Given </u><u>Expression</u><u> </u><u>:</u><u>-</u><u> </u>

\sf\implies \dfrac{ cos^2\theta -1}{4 \ sin^2\theta }

<u>Using </u><u>Identity</u><u> </u><u>:</u><u>-</u><u> </u>

\sf\implies \red{ sin^2\theta + cos^2\theta = 1}

<u>So </u><u>that</u><u> </u><u>:</u><u>-</u><u> </u>

\sf\implies - sin^2\theta = cos^2\theta -1

<u>We </u><u>have</u><u> </u><u>:</u><u>-</u><u> </u>

\sf\implies \dfrac{ cos^2\theta -1}{4 \ sin^2\theta } \\\\\sf\implies\dfrac{ - sin^2\theta}{4sin^2\theta}=\boxed{\sf -\dfrac{1}{4}}

<u>Hence </u><u>the</u><u> </u><u>required</u><u> answer</u><u> is</u><u> </u><u>-</u><u>1</u><u>/</u><u>4</u><u>. </u>

5 0
3 years ago
An object falls from a position of rest and
kumpel [21]

Answer:

About 4.1323 meters.

Step-by-step explanation:

We can use the following kinematic equations:

\displaystyle v_f  = v_0 + at \text{ and } \Delta d = v_0 t + \frac{1}{2} at^2

We want to determine the distance the object has dropped after falling from rest and reaching an instantenous speed of 9 m/s.

We are given that the acceleration due to gravity is 9.8 m/s².

Using this fact and the first equation, find the time for which it took the object to reach 9 m/s. Note that the initial velocity is 0 m/s since the object started from rest.

\displaystyle \begin{aligned} v_f = v_0 + at \\ \\ (9\text{ m/s}) & = (0\text{ m/s}) + (9.8\text{ m/s$^2$})t \\ \\ 9\text{ m/s} & = (9.8 \text{ m/s$^2$})t \\ \\ t &\approx0.9184 \text{ s} \end{aligned}

To find how far the object dropped, we can use the second equation:

\displaystyle\begin{aligned}  \Delta d & = v_0 t + \frac{1}{2} at^2 \\ \\  & = (0\text{ m/s})(0.9184 \text{ s}) + \frac{1}{2}(9.8 \text{ m/s$^2$})(0.9184 \text{ s})^2 \\ \\ & = 4.1323 \text{ m} \end{aligned}

In conclusion, the object would have dropped about 4.1323 meters.

6 0
3 years ago
Einsteinium-
Natalija [7]

Answer:

                 S(t)=450(2/3)^t

Explanation:

The question is "Einstenium-253 is an element that loses about 2/3 of its mass every month. A sample of einstenium-253 has 450 grams. Write a function that gives the sample's mass in grams, S(t) from today".

Since <em>einstenium-253 loses about 2/3 of its mass every month</em>, you can model the amount of sample by an exponential decay function, which is a geometric progression with a growing factor less than 1.

The general form of an exponential decay function is:

y=A_0r^t

Where:

  • A₀ is the initial value
  • r is the growing or decaying factor
  • t is the time
  • y is the value of the function at time t.

In this case, you have:

  • A₀ = 450
  • r = 2/3
  • t = t
  • y = S(t)

Now you can replace the values in the model and will obtain:

                  S(t)=450(2/3)^t

4 0
3 years ago
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lesya692 [45]

Answer:

the slope rise/run = 4/6

4 0
3 years ago
Which transformations could have occurred to
Semmy [17]

Step-by-step explanation:

•a reflection and a dilation

8 0
3 years ago
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