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2 years ago

If Sin x = -¼, where π < x < 3π∕2 , find the value of Cos 2x

Mathematics

1 answer:

Sliva [168]2 years ago

5 0

Answer: 7/8

Cos2x has 3 formulas, Sinx is given in the question, we should use the formula with sinus. I guess that's the solution.

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What is 70/6 times 18/4 in simplest form

Alenkasestr [34]

70/6 × 18/4

70 * 18/6*4. cross out 18 and 6.

= 70*3/4

= 35 * 2 * 3/ 2*2

= 35*3/2

= 105/2

= 52.5

OR

52 1/2.

6 0

3 years ago

Read 2 more answers

9,000 + 40 + 0.1 + 0.008 I need to put it in standard form. Please help!

Andre45 [30]

Answer:

-12

Step-by-step explanation:

8 0

3 years ago

5 less than a number is equivalent to 1 more than three times the number. the number is

lutik1710 [3]

Answer:

x = -1

Step-by-step explanation:

5 less than a number is equivalent to 1 more than three times the number

number = x

x - 5 = 3x + 1

now im going to get the numbers and variable on different sides

x - 5 + 5 = x

3x + 1 - 3x = 1

x + 3x = 4x

1 - 5 = -4

4x = -4

lastly im going to divide each side by 4

4x / 4 = x

-4 / 4 = -1

x = -1

3 0

3 years ago

11. The news reports that today's high temperature is 16°F colder than

LenaWriter [7]

Answer:

2x3+6x2/5x3 thats the expression

Step-by-step explanation:

3 0

2 years ago

The coordinates of the endpoints of AB and CD are A(2,

Ratling [72]

Answer:

Option 1: CD is a perpendicular bisector of AB

Step-by-step explanation:

Let us find out the slopes of various line segments and the Distances and then we will draw the conclusions accordingly.

Formula to find slope

$m= \frac{y_2-y_1}{x_2-x_1}$

Formula to Find Distance between two points

$D=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}$

mAB ( represents , Slope of AB )

1. $mAC= \frac{3-2}{2-5}=\frac{1}{-3}=-\frac{1}{3}$

2. $mBC=\frac{2-1}{5-8}=\frac{1}{-3}=-\frac{1}{3}$

3. $mCD=\frac{5-2}{6-5}=\frac{3}{1}=3$

4. $AC=\sqrt{(3-2)^2+(2-5)^2} =\sqrt{(1)^2+(-3)^2}=\sqrt{1+9}=\sqrt{10}$

5. $BC=\sqrt{(2-1)^2+(5-8)^2} =\sqrt{(1)^2+(-3)^2}=\sqrt{1+9}=\sqrt{10}$

mAC = mBC , and C is common point , hence these three are collinear points making a straight line whole slope is $-\frac{1}{3}$

$mAB=-\frac{1}{3}$

$mCD=3$

$mAB \times mCD = -\frac{1}{3} \times 3 = -1$

Hence CD ⊥ AB

Also

From Point 4 and point 5 above , we see that

AC = CB

Hence CD bisect AB at C, also CD ⊥ AB

There fore

CD is a perpendicular bisector of AB

Therefor option 1 is true

4 0

3 years ago