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Damm [24]
2 years ago
10

Henry's Moving Company charges an initial fee of $50 plus $20 per hour (h). The total cost

Mathematics
1 answer:
emmasim [6.3K]2 years ago
7 0

Answer:

Jones moving company would be cheaper

Step-by-step explanation:

Henry: total = 50+20(10) = 250

Jones: total = 100+10(10) = 200

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How do you get angle x using trigonometry in a right angled triangle?
Scorpion4ik [409]

Answer:

Example

Step 1 The two sides we know are Adjacent (6,750) and Hypotenuse (8,100).

Step 2 SOHCAHTOA tells us we must use Cosine.

Step 3 Calculate Adjacent / Hypotenuse = 6,750/8,100 = 0.8333.

Step 4 Find the angle from your calculator using cos-1 of 0.8333:

3 0
3 years ago
Solve. 3(x-6)-2(2x+3)=14
coldgirl [10]

Answer:

x=-38

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

3(x−6)−2(2x+3)=14

(3)(x)+(3)(−6)+(−2)(2x)+(−2)(3)=14(Distribute)

3x+−18+−4x+−6=14

(3x+−4x)+(−18+−6)=14(Combine Like Terms)

−x+−24=14

−x−24=14

Step 2: Add 24 to both sides.

−x−24+24=14+24

−x=38

Step 3: Divide both sides by -1.

−x

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=

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5 0
3 years ago
Read 2 more answers
4b-4=3b+4<br> solve for b
damaskus [11]

Answer:

4b-3b=4+4

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Step-by-step explanation:

Hence, the value of b is 8

#hope it helps

6 0
3 years ago
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Which expression is equivalent to...
torisob [31]

Answer:

x^{\frac{2}{7} } y^{-\frac{3}{5} } \\  i.e answer A.

Step-by-step explanation:

This question involves knowing the following power/exponent rule:

\sqrt[n]{x^m} = x^\frac{m}{n} \\\\so \sqrt[7]{x^2} = x^\frac{2}{7} \\\\and  \\\\ \sqrt[5]{y^3} = y^\frac{3}{5} \\

Next, when a power is on the bottom of a fraction, if we want to move it to the top, this makes the power become negative.

so the y-term, when moved to the top of the fraction, becomes:

y^{-\frac{3}{5} } \\

So the answer is: x^{\frac{2}{7} } y^{-\frac{3}{5} } \\

7 0
3 years ago
Find a degree 3 polynomial with real coefficients having zeros 4 and 2i and a lead coefficient of 1. Write P
iren2701 [21]

Answer:

x^2 - 2xi - 4x +8i

Step-by-step explanation:

(x -4) (x -2i) (x+2i)

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