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jeka57 [31]
3 years ago
11

John's commute to work is 20kmhr while Sheri's commute is 500mmin. Who has the fastest commute to work in mihrif 1.61km=1mi? A S

heri has the faster commute by 6.2mihr. B Sheri has the faster commute by 16.1mihr. C Sheri has the faster commute by 18.7mihr. D Sheri has the faster commute by 48.3mihr.
Mathematics
1 answer:
Andreyy893 years ago
3 0

Answer:

A) Sheri has the faster commute by 6.2 miles/hr.

Step-by-step explanation:

Given

John's commute to work =20\ km/hr

Sheri's commute to work  =500\ m/min

1.61\ km = 1\ mile

John's commute to work in miles per hour = \frac{20\ km}{1 hr}\times \frac{1\ mile}{1.61\ km}= 12.42\ miles/hr

Sheri's commute to work in miles per hour =\frac{500\ m}{1\ min}\times \frac{1\ km}{1000\ m}\times \frac{1\ mile}{1.61\ km}\times \frac{60\ min}{1\ hr}= 18.63\ miles/ hr

We can see that Sheri has a faster commute.

Difference between the rates =18.63\ miles/ hr-12.42\ miles/hr=6.21\ miles/hr\approx 6.2\ miles/hr

∴ Sheri has the faster commute by 6.2 miles/hr.

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<h2><em><u>2/9 is the answer.</u></em></h2>

Step-by-step explanation:

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2 years ago
Answer with the explanation step by step
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The answer is A. \frac{3(x-21)}{(x+7)(x-7)}.

Step-by-step explanation:

To find the difference of this problem, start by simplifying the denominator, which will look like \frac{3}{x+7}-\frac{42}{(x+7)(x-7)}. Next, multiply \frac{3}{x+7} by \frac{x-7}{x-7}  to create a fraction with a common denominator in order to subtract from \frac{42}{(x+7)(x-7)}. The problem will now look like \frac{3}{x+7}*\frac{x-7}{x-7}-\frac{42}{(x+7)(x-7)}.  

Then, simplify the terms in the problem by first multiplying \frac{3}{x+7} and \frac{x-7}{x-7}, which will look like \frac{3(x-7)}{(x+7)(x-7)}-\frac{42}{(x+7)(x-7)}. The next step is to combine the numerators over the common denominator, which will look like \frac{3(x-7)-42}{(x+7)(x-7)}.

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