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klemol [59]
3 years ago
5

Select all the proper fractions.

Mathematics
1 answer:
zubka84 [21]3 years ago
6 0

Answer:

what are the fractions?

Step-by-step explanation:

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The dimensions in inches of a shipping box at we ship 4 you can be expressed as width x, length x+5, and height 3x-1. The volume
MakcuM [25]

Answer:

Connexus: C,D,C,A,A.

Step-by-step explanation:

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Kelly walked 3 miles.Abby walk 3/4 of a mile how far did they walk in all
timofeeve [1]

Answer:

3 3/4

Step-by-step explanation:

Add the two numbers:

3 + 3/4 = 3 3/4

3 3/4 is the amount walked in all.

~

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A shoe store uses a 60​% markup for all of the shoes it sells. What would be the selling price of a pair of shoes that has a who
NARA [144]

Answer:

33.33 percent

Step-by-step explanation:

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3 years ago
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an airplane begins to descend for a landing. the elevation g (in feet) of the airplane is modeled by the function: g(t)= 4800-30
Fynjy0 [20]

Answer:

The y-intercept in this case is 4800

Step-by-step explanation:

The equation of a line graph is ;

y = mx + c

with respect to the given equation in the question, the y-intercept in this case is 4,800

In this case the y-intercept represent the height from which the plane starts to descend

7 0
3 years ago
In a casino in Blackpool there are two slot machines (machine 1 and machine 2): one that pays out 10 % of the time, and one that
otez555 [7]

Answer:

Given that;

a)

2 machines, 1 and 2

Machine 1

pays 10% of times when the machine is generous

So the probability that the machine 1 pays given that its generous is

P (Pays/machine 1 is generous) = 10% = 0.10

Machine 2  

pays 20% of times when its generous

i.e the probability that the machine pays given that its generous is;

P (Pays / machine 2 is generous) = 20% = 0.20

Also we assume there is equal chance of being generous

i.e

P(machine 1 is generous) = P(machine 2 is generous ) = 0.5  

b)

this is to help obtain the probability that machine 1 is generous given that the player loose in the first bet,

i.e P(machine 1 is generous / lost)  

c)

Since, the probability that the machine is generous is 0.5,

it can be said that there is 50% chance that machine 1 is generous when the player loses the first bet

d)

therefore The required probability is calculated as;

P(machine 1 is generous/lost) = p(machine 1 is generous ∩ lost) / p (lost)

= [p(lost/machine 1 is generous) × p(machine 1 is generous)] / [{(1-p(pays/machine 1 is generous)) × p(machine 1 is generous)} + {((1-p(pays/machine 2 is generous)) × p(machine 2 is generous)}]

= [(1 - p(pays/machine 1 is hereous)) × p(machine 1 is generous)] × [(( 1- 0.10) × 0.5) + ((1 - 0.20) × 0.5)]

= ( 1- 0.10) × 0.5) / 0.85

= 0.5294

so  the probability that the player loses the first bet given that the machine is generous is 0.5294

e)

Since the gotten probability that the player loses the first bet given that machine 1 is generous is close to 0.50 then it can be said that the probability is consistent with the expectations.

5 0
3 years ago
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