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IceJOKER [234]
2 years ago
6

A swimming pool has a diameter of 24 feet. What is the minimum amount of fabric needed to cover the pool if the cover must hang

off by 1 foot all around the pool?
Mathematics
1 answer:
Alika [10]2 years ago
5 0

Answer:

531.167 ft²

Step-by-step explanation:

Given data

Dimension of pool

Diameter =24ft

Radius =12ft

If the cover must hang by 1ft around, then the diameter is 26ft

Radius =13ft

Area of cover = πr²

Substitute

Area = 3.142*13²

Area =3.143*169

Area =531.167 ft²

Hence the minimum area is 531.167 ft²

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Please give me the answers to all three I will mark u brilliant
elixir [45]

Answer:

First know the formula for the area of a circle;

<h2>A = πr^{2}</h2>

Where 'π' represents pi(3.14 or 22/7), and 'r' stands for the radius being squared.

For the first problem, we can see that 12 is our <u>diameter</u>.

And to find the radius, we need to find 1/2 of the diameter (half of the diameter), so;

D/2 = R

Replace with actual values;

12/2 = 6, <u>6</u> is our <u>radius</u>.

Now we plug this into our formula:

A = πr^{2}

A = 3.14(6^2)

A = 3.14(36)

A = <u>113.04 centimetres</u> is the area of the circle.

For the second problem, we can see that 18 is our <u>diameter</u>.

And to convert the diameter into the radius, we do what we did to the past problem, find 1/2 of the diameter.

So;

D/2 = R

18/2 = 9, <u>9</u> is our <u>radius</u>.

Now we plug this into our formula:

A = πr^{2}

A = 3.14(9^2)

A = 3.14(81)

A = <u>254.34 inches</u> is the area for this circle.

For the third problem, we can see that our radius is already given, 5.

So now we just simply and easily plug this into our formula;

A = πr^{2}

A = 3.14(5^2)

A = 3.14(25)

A = <u>78.5 meters</u> is the area for this circle.

4 0
2 years ago
Let f be the function given by f(x)=ln x/x for all x 0. the derivative of f is given by
Dmitriy789 [7]
Using the quotient rule

f'(x)  =   x * 1/x  - ln x          1 - ln x
            -----------------   =      ---------  <-------- ur answer
                  x^2                     x^2
6 0
3 years ago
Find the difference. (7x-6 2/3) - (-3x + 4 3/4)
NikAS [45]

10x-61/12 is the difference of  (7x-6\frac{2}{3}) - (-3x + 4\frac{3}{4}).

<h3>What is Expression?</h3>

An expression is combination of variables, numbers and operators.

The given expression is (7x-6\frac{2}{3}) - (-3x + 4\frac{3}{4})

7x-6\frac{2}{3}+3x- 4\frac{3}{4}

7x-20/3+3x-19/4

Add the variable terms and constant terms.

10x-20/3-19/4

The LCM of 3 and 4 is 12/

10x-4-57/12

10x-61/12

Hence, 10x-61/12 is the difference of  (7x-6\frac{2}{3}) - (-3x + 4\frac{3}{4}).

To learn more on Expressions click:

brainly.com/question/14083225

#SPJ1

4 0
1 year ago
NEED ANSWER ASAP!!<br> Find x
sineoko [7]

Step-by-step explanation:

\frac{48}{2x + 7}  =  \frac{40}{5x - 2}  \\ 48(5x - 2) = 40(2x + 7) \\ 240x - 96 = 80x + 280 \\ 240x - 80x = 96 + 280 \\ 160x = 376 \\  \frac{160x}{160}  =  \frac{376}{160}  \\ x = 2.35

6 0
4 years ago
5. Which polynomial is equal to (x5 + 1) divided by (x + 1)?
Mkey [24]

Answer:

B  x^4-x^3+x^2-x+1

Step-by-step explanation:

Given,

Dividend = (x^5+1)

Divisor = (x+1)

Step 1: First The dividend is (x^5+1) and Divisor is (x+1) when divided first time the quotient will be x^4 and remainder will be -x^4+1

Step: 2 Now the new dividend is -x^4+1 and Divisor is (x+1)  when divided the quotient will be x^4-x^3 and remainder will be x^3+1

Step: 3 Now the new dividend is x^3+1 and Divisor is (x+1)  when divided the quotient will be x^4-x^3+x^2 and remainder will be -x^2+1

Step: 4 Now the new dividend is -x^2+1 and Divisor is (x+1)  when divided the quotient will be x^4-x^3+x^2-x and remainder will be x+1

Step: 5 Now the new dividend is x+1 and Divisor is (x+1)  when divided the quotient will be x^4-x^3+x^2-x+1 and remainder will be 0.

Hence When the polynomial (x^5+1) is divided by  (x+1) the answer or quotient will be equal to  x^4-x^3+x^2-x+1 and remainder will be 0.

5 0
3 years ago
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