Answer:
a. 9.2 x 10-2 M
Step-by-step explanation:
i took test
Answer:
3yz² - 3z² - 5y + 7
Step-by-step explanation:
Sum of two polynomials = –yz² - 3z² – 4y + 4
One of the polynomial = y - 4yz²- 3
Find the other polynomial
The other polynomial = sum of the polynomials - one of the polynomial
= –yz² - 3z² – 4y + 4 - (y - 4yz² - 3)
= –yz² - 3z² – 4y + 4 - y + 4yz² + 3
= -yz² + 4yz² - 3z² - 4y - y + 4 + 3
= 3yz² - 3z² - 5y + 7
A. 0 -2yz?
B. – 4y + 7 01 - 2yz
C. – 3y + 1 0 -5yz² + 3z² – 3y + 1 D. 3yz² - 3z² – 5y + 7
Answer:
x = 65
Step-by-step explanation:
using the Altitude- on- Hypotenuse theorem
(leg of big Δ )² = (part of hypotenuse below it ) × (whole hypotenuse)
x² = 25 × 169 = 4225 ( take square root of both sides )
x =
= 65
a
0
=
4
a
i
=
a
i
−
1
+
7
XXXX
possibly with the restriction 1<=i<=4 if this is not intended to be a continuous sequence
Explanation:
This is a simple arithmetic sequence with a difference of
7
between ascending sequence terms.
Answer:
Step-by-step explanation:
Given that four people are on the team. Members will be chosen randomly to serve as chairperson, treasurer, secretary, or timekeeper
Since one person cannot serve two posts we have total number of ways
= 4(3)(2)(1) = 24
If Noor is chair person and Qu treasurer then remaining 2 can take two posts in 2 different ways
So probability that Noor is selected to be chairperson and Qu is selected to be treasurer
=favourable outcomes/total outcomes
= 