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Anuta_ua [19.1K]
3 years ago
14

Point M is on line segment LN. Given LN=4x, MN= x, and LM=3, determine the numerical length of LN.

Mathematics
2 answers:
Basile [38]3 years ago
8 0

Answer:

?? i dont know men this is not the answer

Step-by-step explanation:

Artyom0805 [142]3 years ago
8 0

Answer:

LN = 4 units

Step-by-step explanation:

Since M is on LN , then

LN = LM + MN , that is

4x = 3 + x ( subtract x from both sides )

3x = 3 ( divide both sides by 3 )

x = 1

Then

LN = 3 + x = 3 + 1 = 4

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(5 + 4) + (2 + 6) = 10 +__<br><br> Find the missing number.
LUCKY_DIMON [66]

Answer:

The Missing number is 7

Step-by-step explanation:

5+4=9

2+6=8

9+8=17

And if the equations are supposed to have the same answer then you add 7 to 10 and they both have the same answer.

<em><u>Could I please have BRAINLIEST.</u></em>

4 0
4 years ago
Two numbers total 63 and have a difference of 31. Find the two numbers
Anastaziya [24]

Answer: 47 and 16

Step-by-step explanation:

- Make Two Equations

x + y = 63

x - y = 31

- Set one of the equations equal to one of the variables

x + y = 63

x = 31 + y

- Substitute the equation back into the other one

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31 + 2y = 63

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5 0
3 years ago
Read 2 more answers
Can you please help me out
Taya2010 [7]

The bag contains,

Red (R) marbles is 9, Green (G) marbles is 7 and Blue (B) marbles is 4,

Total marbles (possible outcome) is,

\text{Total marbles = (R) + (G) +(B) = 9 + 7 + 4 = 20 marbles}

Let P(R) represent the probablity of picking a red marble,

P(G) represent the probability of picking a green marble and,

P(B) represent the probability of picking a blue marble.

Probability , P, is,

\text{Prob, P =}\frac{required\text{ outcome}}{possible\text{ outcome}}\begin{gathered} P(R)=\frac{9}{20} \\ P(G)=\frac{7}{20} \\ P(B)=\frac{4}{20} \end{gathered}

Probablity of drawing a Red marble (R) and then a blue marble (B) without being replaced,

That means once a marble is drawn, the total marbles (possible outcome) reduces as well,

\begin{gathered} \text{Prob of a red marble P(R) =}\frac{9}{20} \\ \text{Prob of }a\text{ blue marble =}\frac{4}{19} \\ \text{After a marble is selected without replacement, marbles left is 19} \\ \text{Prob of red marble + prob of blue marble = P(R) + P(B) = }\frac{9}{20}+\frac{4}{19}=\frac{251}{380} \\ \text{Hence, the probability is }\frac{251}{380} \end{gathered}

Hence, the best option is G.

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2 years ago
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lianna [129]

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52.63              

Step-by-step explanation:

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