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rewona [7]
3 years ago
13

If mZADB = 15 then what is m ACB? A B D

Mathematics
1 answer:
ASHA 777 [7]3 years ago
8 0
D Do you because you have to get it to equal 15
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12a^-4b^4c^5/3a^6b^-2c^2 =
ollegr [7]
Download Photomath. Answers every question by taking a pic of the problem! Hope this helps
5 0
3 years ago
An executive in an engineering firm earns a monthly salary plus a Christmas bonus of $9300. If she earns a total of $86,100 per
VARVARA [1.3K]

86,100-9300=76,800

76,800/12=6,400

Monthly salary is 6,400.

6 0
4 years ago
The blood platelet counts of a group of women have a bell-shaped distribution with a mean of 257.62 and a standard deviation of
Effectus [21]

Answer:

(a) Approximately 68 % of women in this group have platelet counts within 1 standard deviation of the mean, or between 195.5 and 319.7.

(b) Approximately 99.7% of women in this group have platelet counts between 71.3 and 443.9.

Step-by-step explanation:

We are given that the blood platelet counts of a group of women have a bell-shaped distribution with a mean of 257.62 and a standard deviation of 62.1

Let X = <u><em>the blood platelet counts of a group of women</em></u>

So, X ~ Normal(\mu=257.62, \sigma^{2} =62.1^{2})

Now, the empirical rule states that;

  • 68% of the data values lie within the 1 standard deviation of the mean.
  • 95% of the data values lie within the 2 standard deviations of the mean.
  • 99.7% of the data values lie within the 3 standard deviations of the mean.

(a) The approximate percentage of women with platelet counts within 1 standard deviation of the mean, or between 195.5 and 319.7 is 68% according to the empirical rule.

(b) The approximate percentage of women with platelet counts between 71.3 and 443.9 is given by;

       z-score of 443.9 =  \frac{X-\mu}{\sigma}

                                   =  \frac{443.9-257.62}{62.1}  = 3

       z-score of 71.3 =  \frac{X-\mu}{\sigma}

                                =  \frac{71.3-257.62}{62.1}  = -3

So, approximately 99.7% of women in this group have platelet counts between 71.3 and 443.9.

5 0
3 years ago
The increase in the number of humans living on Earth (N, as measured in billions) with time t (as measured in years since 1800)
NemiM [27]

Answer:

The slope of the line would be 0.00910 in a logarithm graphic.

Step-by-step explanation:

Statement is incomplete. The correct sentences are:<em> The increase in the number of humans living on Earth (N, as measured in billions) with time t (as measured in years since 1800) is modeld by the following function: N = 0.892e^0.00910t. If you were to graph in ln (N) versus t, what would be the slope of the line?</em>

Let be N(t) = 0.892\cdot e^{0.00910\cdot t}, where N(t) is the number of humans living on Earth, measured in billions, and t is the time, measured in years since 1800. As we notice, this is an exponential function and its slope is not constant and such expression have to be linearized by using a logartihm graphic. We add logarithms on each side of the formula and simplify the resulting expression by means of logarithmic properties:

\log N(t) = \log \left(0.892\cdot e^{0.00910\cdot t}\right)

\log N(t) = \log 0.892 + 0.00910\cdot t

In a nutshell, the slope of the line would be 0.00910 in a logarithm graphic.

4 0
3 years ago
Answer fast please<br>Drag and drop each number to its correct position on the number line.
Vsevolod [243]

Answer:

-1 is the first one to the left of the 0

-5 is the 5th one to the left of the 0

2 is the 2nd one to the right of the 0

4 is the 4th one to the right of the 0

Step-by-step explanation:

hope this helped!

it would be cool if you gave me the brainliest.

4 0
4 years ago
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